> > > > Challenge 3: do it faster and with less code.
> > it should work even if the file is too large
> > to fit in memory (as long as each individual line fits in memory).
def getline(filename, lineno):
if lineno < 1:
return ''
f = open(filename)
g = f.readline
return (reduce(lambda x,y: g(), range(lineno), ''), f.close())[0]
This incorporates a couple of ideas inspired by Tim's post.
Raymond Hettinger
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