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Showing content from https://mail.python.org/pipermail/python-dev/2001-September/017443.html below:

[Python-Dev] warning in _localemodule.c patch

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> The other option is to cast the pointer in the call to free().

Sounds like the better solution.

Publicly, it's a const.  Privately, you happen to malloc() and free()
it.

--Guido van Rossum (home page: http://www.python.org/~guido/)

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