> string_compare() could special-case pointer equality too, although I suspect
> doing so would be a net loss.
I've done some measurements here, too, again taking your example
from time import clock
indices = [1] * 1000000
def doit():
s = clock()
for i in indices:
"ab" < "ab"
f = clock()
return f - s
for i in xrange(10):
print "%.3f" % doit()
This is the case where testing for identity helps. Running it without
identity test takes 0.74s, running it with identity test takes 0.68s.
Now, looking at the case of non-identical pointers, I could not find
any measurable difference. After increasing the number of rounds by a
factor of ten, I got, without identity test
6.920
6.920
6.910
6.970
7.080
6.920
6.920
6.910
6.930
6.920
With identity test, I got
6.930
6.930
6.920
7.080
6.920
6.930
6.960
6.930
6.920
6.920
That still does not look like a significant difference to me.
Regards,
Martin
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