You're quite right! I've checked in a change, renaming it to "outf". Cheers, -g On Thu, Jan 11, 2001 at 05:08:29PM +0800, Mark Favas wrote: > On Tru64 Unix, with Compaq's C/CXX compilers, the current CVS version of > sysmodule.c produces the following errors: > > cc -O -Olimit 1500 -I./../Include -I.. -DHAVE_CONFIG_H -c -o > sysmodule.o sysmodule.c > cc: Error: sysmodule.c, line 73: Invalid declarator. (declarator) > PyObject *o, *stdout; > ----------------------^ > cc: Error: sysmodule.c, line 79: In this statement, "o" is not declared. > (undeclared) > if (!PyArg_ParseTuple(args, "O:displayhook", &o)) > ------------------------------------------------------^ > cc: Error: sysmodule.c, line 93: In this statement, "(&_iob[1])" is not > an lvalue, but occurs in a context that requires one. (needlvalue) > stdout = PySys_GetObject("stdout"); > --------^ > cc: Warning: sysmodule.c, line 98: In this statement, the referenced > type of the pointer value "(&_iob[1])" is "struct declared without a > tag", which is not compatible with "struct _object". (ptrmismatch) > if (PyFile_WriteObject(o, stdout, 0) != 0) > ----------------------------------^ > cc: Warning: sysmodule.c, line 100: In this statement, the referenced > type of the pointer value "(&_iob[1])" is "struct declared without a > tag", which is not compatible with "struct _object". (ptrmismatch) > PyFile_SoftSpace(stdout, 1); > -------------------------^ > > The problem is that stdout is a macro #define'd in stdio.h as (&_iob[1]) > (stdin and stderr also are similarly #define'd). > > -- > Mark Favas - m.favas@per.dem.csiro.au > CSIRO, Private Bag No 5, Wembley, Western Australia 6913, AUSTRALIA > > _______________________________________________ > Python-Dev mailing list > Python-Dev@python.org > http://www.python.org/mailman/listinfo/python-dev -- Greg Stein, http://www.lyra.org/
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