I don't think I buy your explanation that Python uses dynamic scope
for resolving globals. As I understand the mechanism, the module
namespace and builtins namespace are those for the module in which the
function was defined. If so, this is still static scope.
Here's a quick example that illustrates the difference:
module foo:
-----------------------
a = 12
def add(b):
return a + b
-----------------------
module bar:
-----------------------
from foo import add
a = -1
print add(1)
-----------------------
If Python used static scope, "python bar.py" should print 13 (it
does). If it used dynamic scope, I would expect the answer to be 0.
Jeremy
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