On Fri, Jul 14, 2000 at 03:09:10AM -0700, Ka-Ping Yee wrote: > I actually believe > solve(X.H()*X, X.H()*y) > is *clearer* than > (X'*X)\(X'*y) > (What does the backslash mean? What does the tick mark mean? > At least solve() is clear, and if i understood what H() stood > for, it would mean more than a tick mark.) More importantly, how are they grouped ? Is '* a single operator, or is ' a binary operator and * an unary operator ? Or is ' a postfix unary operator and * the binary operator ? Does the backslash escape the opening paren for some reason, or is it an operator on its own ? Oh, wait, I see it now ! It's a string literal of the new 'X' type, containing '*X)\(X', multiplied by y! I wonder what that 'X' type string is... Maybe a built-in regular expression ? Confusing-ly y'rs, -- Thomas Wouters <thomas@xs4all.net> Hi! I'm a .signature virus! copy me into your .signature file to help me spread!
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