On Thu, 13 Jul 2000, Huaiyu Zhu wrote:
>
> You are almost there. :-) The current MatPy expression is
> solve (X.H() * X, X.H() * y)
I was about to suggest something similar, but you beat me to it.
I think that expression looks great. If you can say it that
concisely, i don't think you need to throw in extra operators
at all (let alone a half-dozen of them that are incomprehensible
to anyone outside of the Matlab community).
I actually believe
solve(X.H()*X, X.H()*y)
is *clearer* than
(X'*X)\(X'*y)
(What does the backslash mean? What does the tick mark mean?
At least solve() is clear, and if i understood what H() stood
for, it would mean more than a tick mark.)
-- ?!ng
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