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Showing content from https://learn.microsoft.com/dotnet/csharp/language-reference/builtin-types/numeric-conversions below:

Built-in numeric conversions - C# reference

C# provides a set of integral and floating-point numeric types. There exists a conversion between any two numeric types, either implicit or explicit. You must use a cast expression to perform an explicit conversion.

Implicit numeric conversions

The following table shows the predefined implicit conversions between the built-in numeric types:

From To sbyte short, int, long, float, double, decimal, or nint byte short, ushort, int, uint, long, ulong, float, double, decimal, nint, or nuint short int, long, float, double, or decimal, or nint ushort int, uint, long, ulong, float, double, or decimal, nint, or nuint int long, float, double, or decimal, nint uint long, ulong, float, double, or decimal, or nuint long float, double, or decimal ulong float, double, or decimal float double nint long, float, double, or decimal nuint ulong, float, double, or decimal

Note

The implicit conversions from int, uint, long, ulong, nint, or nuint to float and from long, ulong, nint, or nuint to double may cause a loss of precision, but never a loss of an order of magnitude. The other implicit numeric conversions never lose any information.

Also note that

Any integral numeric type is implicitly convertible to any floating-point numeric type.
There are no implicit conversions to the byte and sbyte types. There are no implicit conversions from the double and decimal types.
There are no implicit conversions between the decimal type and the float or double types.
A value of a constant expression of type int (for example, a value represented by an integer literal) can be implicitly converted to sbyte, byte, short, ushort, uint, ulong, nint, or nuint, if it's within the range of the destination type:
```
byte a = 13;
byte b = 300;  // CS0031: Constant value '300' cannot be converted to a 'byte'
```
As the preceding example shows, if the constant value is not within the range of the destination type, a compiler error CS0031 occurs.

Explicit numeric conversions

The following table shows the predefined explicit conversions between the built-in numeric types for which there is no implicit conversion:

From To sbyte byte, ushort, uint, ulong, or nuint byte sbyte short sbyte, byte, ushort, uint, ulong, or nuint ushort sbyte, byte, or short int sbyte, byte, short, ushort, uint, ulong, or nuint uint sbyte, byte, short, ushort, int, or nint long sbyte, byte, short, ushort, int, uint, ulong, nint, or nuint ulong sbyte, byte, short, ushort, int, uint, long, nint, or nuint float sbyte, byte, short, ushort, int, uint, long, ulong, decimal, nint, or nuint double sbyte, byte, short, ushort, int, uint, long, ulong, float, decimal, nint, or nuint decimal sbyte, byte, short, ushort, int, uint, long, ulong, float, double, nint, or nuint nint sbyte, byte, short, ushort, int, uint, ulong, or nuint nuint sbyte, byte, short, ushort, int, uint, long, or nint

Note

An explicit numeric conversion might result in data loss or throw an exception, typically an OverflowException.

Also note that:

When you convert a value of an integral type to another integral type, the result depends on the overflow-checking context. In a checked context, the conversion succeeds if the source value is within the range of the destination type. Otherwise, an OverflowException is thrown. In an unchecked context, the conversion always succeeds, and proceeds as follows:
- If the source type is larger than the destination type, then the source value is truncated by discarding its "extra" most significant bits. The result is then treated as a value of the destination type.
- If the source type is smaller than the destination type, then the source value is either sign-extended or zero-extended so that it's of the same size as the destination type. Sign-extension is used if the source type is signed; zero-extension is used if the source type is unsigned. The result is then treated as a value of the destination type.
- If the source type is the same size as the destination type, then the source value is treated as a value of the destination type.
When you convert a decimal value to an integral type, this value is rounded towards zero to the nearest integral value. If the resulting integral value is outside the range of the destination type, an OverflowException is thrown.
When you convert a double or float value to an integral type, this value is rounded towards zero to the nearest integral value. If the resulting integral value is outside the range of the destination type, the result depends on the overflow-checking context. In a checked context, an OverflowException is thrown, while in an unchecked context, the result is an unspecified value of the destination type.
When you convert double to float, the double value is rounded to the nearest float value. If the double value is too small or too large to fit into the float type, the result is zero or infinity.
When you convert float or double to decimal, the source value is converted to decimal representation and rounded to the nearest number after the 28th decimal place if necessary. Depending on the value of the source value, one of the following results may occur:
- If the source value is too small to be represented as a decimal, the result becomes zero.
- If the source value is NaN (not a number), infinity, or too large to be represented as a decimal, an OverflowException is thrown.
When you convert decimal to float or double, the source value is rounded to the nearest float or double value, respectively.

C# language specification

For more information, see the following sections of the C# language specification: