When ResourceInfo encounters a resource of type 4 (RT_MENU), it creates an object of type MenuResource which contains either a MenuTemplate or a MenuExTemplate. These structures represent a single menu template in a standard or extended 32-bit format and include a collection of MenuTemplateItem or MenuExTemplateItem controls respectively.
The following example loads all menu resources from a file.
string filename = Path.Combine(Environment.GetVariable("WINDIR"), "explorer.exe");
using (ResourceInfo ri = new ResourceInfo())
{
ri.Load(filename);
foreach(MenuResource rc in ri[Kernel32.ResourceTypes.RT_MENU])
{
Console.WriteLine("MenuResource: {0}, {1}", rc.Name, rc.TypeName);
Console.WriteLine(rc.ToString());
}
}
Explorer.exe on Windows Vista contains several standard and extended menu resources, including the following.
MenuResource: 204, RT_MENU
MENUEX 0
BEGIN
MENUITEM "", 129
MENUITEM SEPARATOR
POPUP "&Programs"
BEGIN
MENUITEM "(Empty) ", 513
END
POPUP "F&avorites"
BEGIN
MENUITEM "(Empty) ", 4294967295
END
POPUP "&Documents"
BEGIN
MENUITEM "(Empty) ", 514
END
POPUP "&Settings"
BEGIN
MENUITEM "&Control Panel", 505
MENUITEM SEPARATOR
MENUITEM "&Windows Security...", 5001
MENUITEM "&Network Connections", 557
MENUITEM "&Printers", 510
MENUITEM "&Taskbar and Start Menu", 413
END
POPUP "Sear&ch"
BEGIN
MENUITEM SEPARATOR
END
MENUITEM "&Help and Support", 503
MENUITEM "&Run...", 401
MENUITEM SEPARATOR
MENUITEM "S&ynchronize", 553
MENUITEM "&Log Off %s...", 402
MENUITEM "D&isconnect...", 5000
MENUITEM "Undock Comput&er", 410
MENUITEM "Sh&ut Down...", 506
END
MenuResource: 210, RT_MENU
MENUEX 0
BEGIN
MENUITEM "", 129
MENUITEM "Ca&scade", 403
MENUITEM "Show Windows S&tacked", 405
MENUITEM "Show Windows S&ide by Side", 404
MENUITEM "&Minimize Group", 311
MENUITEM SEPARATOR
MENUITEM "&Close Group", 48913
END
The following example loads a single menu resource directly, without enumerating all resources.
string filename = Path.Combine(Environment.GetVariable("WINDIR"), "explorer.exe");
MenuResource rc = new MenuResource();
rc.Name = new ResourceId(204);
rc.LoadFrom(filename);
Console.WriteLine("MenuResource: {0}, {1}", rc.Name, rc.TypeName);
Console.WriteLine(rc.ToString());
In order to embed a menu into an executable (.exe or .dll) create a new instance of MenuTemplate or a MenuExTemplate, add menu items, assign it to a MenuResource and save it to the destination file. You may also copy a menu from one file to another, etc.
source sourceFilename = ...
string targetFilename = ...
MenuResource sourceMenu = new MenuResource();
sourceMenu.Name = new ResourceId("MENUID");
sourceMenu.LoadFrom(sourceFilename);
sourceMenu.SaveTo(targetFilename);
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