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Showing content from https://github.com/pandas-dev/pandas/issues/47819 below:

Add `axis` parameter to `add_prefix` and `add_suffix` · Issue #47819 · pandas-dev/pandas · GitHub

Feature Type Problem Description

df.add_prefix and df.add_suffix can be used on columns only.
Would be super handy if it can be used on the index to.
Preferably with the option inplace.

Example:

import pandas as pd
import numpy as np

np.random.seed(123)
data = np.random.randint(0, 100, size=(4, 3))
df = pd.DataFrame(data, index=range(1, 5), columns=range(20, 23))
df.index.name = 'Quarter'

DataFrame:

         20  21  22
Quarter            
1        66  92  98
2        17  83  57
3        86  97  96
4        47  73  32

New feature:

df.add_prefix('Q', axis=0, inplace=True)
df.add_prefix(20, axis=1, inplace=True)

Expected result:

         2020  2021  2022
Quarter                  
Q1         66    92    98
Q2         17    83    57
Q3         86    97    96
Q4         47    73    32

Implementation suggestion:

# columns
if df.columns is RangeIndex:
    df.columns = df.columns + 2000 # df.columns stays RangeIndex
else:
   df = df.add_prefix(20) # df.columns becomes list of integers

# index
if df.index is RangeIndex:
    df.set_index(df.index + 2000, inplace=True)
if all(isinstance(idx, int) for idx in list(df.index)): # df.index is list of integers
    df.set_index([int(str(prefix) + str(idx)) for idx in df.index], inplace=True)
else:
    df.set_index([str(prefix) + str(idx) for idx in df.index], inplace=True)
Feature Description
df.add_prefix('Q', axis=0, inplace=True)
df.add_prefix(20, axis=1, inplace=True)
Alternative Solutions

Implementation suggestion:

# columns
if df.columns is RangeIndex:
    df.columns = df.columns + 2000 # df.columns stays RangeIndex
else:
   df = df.add_prefix(20) # df.columns becomes list of integers

# index
if df.index is RangeIndex:
    df.set_index(df.index + 2000, inplace=True)
if all(isinstance(idx, int) for idx in list(df.index)): # df.index is list of integers
    df.set_index([int(str(prefix) + str(idx)) for idx in df.index], inplace=True)
else:
    df.set_index([str(prefix) + str(idx) for idx in df.index], inplace=True)
Additional Context

No response


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