In [2]: from datetime import timedelta
...: from pandas import *
...: td_as_int = [1, 2, 3, 4]
...:
...: def create_data(constructor):
...: return dict((i, {constructor(s): 2*i}) for i, s in enumerate(td_as_int))
...:
...: data_timedelta64 = create_data(lambda x: np.timedelta64(x, 'D'))
...: data_timedelta = create_data(lambda x: timedelta(days=x))
...:
...: result_timedelta64 = DataFrame(data_timedelta64)
...: result_timedelta = DataFrame(data_timedelta)
...:
In [3]: result_timedelta64
Out[3]:
0 1 2 3
1 days 0 NaN NaN NaN
2 days NaN 2 NaN NaN
3 days NaN NaN 4 NaN
4 days NaN NaN NaN 6
In [4]: result_timedelta
Out[4]:
0 1 2 3
1 days NaN NaN NaN NaN
2 days NaN NaN NaN NaN
3 days NaN NaN NaN NaN
4 days NaN NaN NaN NaN
This seems to happen because Timedelta doesn't have hash equality with datetime.timedelta It could easily be worked around here, but I was wondering if there's any reason not to make Timedelta work like Timestamp and match hashes if above a certain resolution?
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