Here is a demo
#include <iostream>
class MyType {
public:
MyType() : a(0) {}
MyType(int i) : a(i) {}
int a;
};
class MyTypeUser {
public:
void use(MyType* a, int count) {
for (int i = 0; i < count; i++) {
std::cout<<a[i].a<<std::endl;
}
}
};
MyTypeUser::use expects an array of MyType. The generated code is only able to hold one MyType actually.
generated MyTypeUser.use definition
public native void use(MyType a, int count);
generated MyType
public class MyType extends Pointer {
static { Loader.load(); }
/** Pointer cast constructor. Invokes {@link Pointer#Pointer(Pointer)}. */
public MyType(Pointer p) { super(p); }
public MyType() { super((Pointer)null); allocate(); }
private native void allocate();
public MyType(int i) { super((Pointer)null); allocate(i); }
private native void allocate(int i);
public native int a(); public native MyType a(int setter);
}
I tried to add the following mapping info following guide here(https://github.com/bytedeco/javacpp/wiki/Mapping-Recipes#specifying-names-to-use-in-java)
infoMap.put(new Info("MyType").pointerTypes("MyTypePointer"));
infoMap.put(new Info("MyTypePointer").valueTypes("MyTypePointer").pointerTypes("@Cast(\"MyType*\") PointerPointer", "@ByPtrPtr MyTypePointer").base("IntPointer"));
The generated code is almost the same.
public native void use(MyTypePointer a, int count);
public class MyTypePointer extends Pointer {
static { Loader.load(); }
/** Pointer cast constructor. Invokes {@link Pointer#Pointer(Pointer)}. */
public MyTypePointer(Pointer p) { super(p); }
public MyTypePointer() { super((Pointer)null); allocate(); }
private native void allocate();
public MyTypePointer(int i) { super((Pointer)null); allocate(i); }
private native void allocate(int i);
public native int a(); public native MyTypePointer a(int setter);
}
Is it possible to define UDT pointer similarly to IntPointer, capable of holding one or more elements? @saudet
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