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std::ranges::for_each, std::ranges::for_each_result - cppreference.com

Call signature

Helper types

1) Applies the given function object f to the result of the value projected by each iterator in the range [first, last), in order.

For both overloads, if the iterator type is mutable, f may modify the elements of the range through the dereferenced iterator. If f returns a result, the result is ignored.

The function-like entities described on this page are algorithm function objects (informally known as niebloids), that is:

• Explicit template argument lists cannot be specified when calling any of them.
• None of them are visible to argument-dependent lookup.
• When any of them are found by normal unqualified lookup as the name to the left of the function-call operator, argument-dependent lookup is inhibited.

{ranges::next(std::move(first), last), std::move(f)}

Exactly ranges::distance(first, last) applications of f and proj.

struct for_each_fn
{
    template<std::input_iterator I, std::sentinel_for<I> S, class Proj = std::identity,
             std::indirectly_unary_invocable<std::projected<I, Proj>> Fun>
    constexpr ranges::for_each_result<I, Fun>
        operator()(I first, S last, Fun f, Proj proj = {}) const
    {
        for (; first != last; ++first)
            std::invoke(f, std::invoke(proj, *first));
        return {std::move(first), std::move(f)};
    }
 
    template<ranges::input_range R, class Proj = std::identity,
             std::indirectly_unary_invocable<std::projected<ranges::iterator_t<R>,
             Proj>> Fun>
    constexpr ranges::for_each_result<ranges::borrowed_iterator_t<R>, Fun>
        operator()(R&& r, Fun f, Proj proj = {}) const
    {
        return (*this)(ranges::begin(r), ranges::end(r), std::move(f), std::ref(proj));
    }
};
 
inline constexpr for_each_fn for_each;

The following example uses a lambda expression to increment all of the elements of a vector and then uses an overloaded operator() in a functor to compute their sum. Note that to compute the sum, it is recommended to use the dedicated algorithm std::accumulate.

#include <algorithm>
#include <cassert>
#include <iostream>
#include <string>
#include <utility>
#include <vector>
 
struct Sum
{
    void operator()(int n) { sum += n; }
    int sum {0};
};
 
int main()
{
    std::vector<int> nums {3, 4, 2, 8, 15, 267};
 
    auto print = [](const auto& n) { std::cout << ' ' << n; };
 
    namespace ranges = std::ranges;
    std::cout << "before:";
    ranges::for_each(std::as_const(nums), print);
    print('\n');
 
    ranges::for_each(nums, [](int& n) { ++n; });
 
    // calls Sum::operator() for each number
    auto [i, s] = ranges::for_each(nums.begin(), nums.end(), Sum());
    assert(i == nums.end());
 
    std::cout << "after: ";
    ranges::for_each(nums.cbegin(), nums.cend(), print);
 
    std::cout << "\n" "sum: " << s.sum << '\n';
 
    using pair = std::pair<int, std::string>; 
    std::vector<pair> pairs {{1,"one"}, {2,"two"}, {3,"tree"}};
 
    std::cout << "project the pair::first: ";
    ranges::for_each(pairs, print, [](const pair& p) { return p.first; });
 
    std::cout << "\n" "project the pair::second:";
    ranges::for_each(pairs, print, &pair::second);
    print('\n');
}

Output:

before: 3 4 2 8 15 267 
after:  4 5 3 9 16 268
sum: 305
project the pair::first:  1 2 3
project the pair::second: one two tree

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