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Showing content from https://en.cppreference.com/w/cpp/language/../ranges/../algorithm/ranges/mismatch.html below:

std::ranges::mismatch, std::ranges::mismatch_result - cppreference.com

Call signature

template< std::input_iterator I1, std::sentinel_for<I1> S1,

          std::input_iterator I2, std::sentinel_for<I2> S2,
          class Pred = ranges::equal_to,
          class Proj1 = std::identity, class Proj2 = std::identity >
requires std::indirectly_comparable<I1, I2, Pred, Proj1, Proj2>
constexpr mismatch_result<I1, I2>
    mismatch( I1 first1, S1 last1, I2 first2, S2 last2,

              Pred pred = {}, Proj1 proj1 = {}, Proj2 proj2 = {} );
(1) (since C++20) template< ranges::input_range R1, ranges::input_range R2,

          class Pred = ranges::equal_to,
          class Proj1 = std::identity, class Proj2 = std::identity >
requires std::indirectly_comparable<
             ranges::iterator_t<R1>, ranges::iterator_t<R2>, Pred, Proj1, Proj2>
constexpr mismatch_result<ranges::borrowed_iterator_t<R1>,
                          ranges::borrowed_iterator_t<R2>>
    mismatch( R1&& r1, R2&& r2, Pred pred = {},

              Proj1 proj1 = {}, Proj2 proj2 = {} );
(2) (since C++20)

Helper types

(3) (since C++20)

Returns the first mismatching pair of projected elements from two ranges: one defined by [first1last1) or r1 and another defined by [first2last2) or r2.

1) Elements are compared using the given binary predicate p.

The function-like entities described on this page are algorithm function objects (informally known as niebloids), that is:

[edit] Parameters first1, last1 - the iterator-sentinel pair defining the first range of elements to compare r1 - the first range of the elements to compare first2, last2 - the iterator-sentinel pair defining the second range of elements to compare r2 - the second range of the elements to compare pred - predicate to apply to the projected elements proj1 - projection to apply to the first range of elements proj2 - projection to apply to the second range of elements [edit] Return value

ranges::mismatch_result with iterators to the first two non-equal elements.

If no mismatches are found when the comparison reaches last1 or last2, whichever happens first, the object holds the end iterator and the corresponding iterator from the other range.

[edit] Complexity

At most std::min(last1 - first1, last2 - first2) applications of the predicate and corresponding projections.

[edit] Possible implementation
struct mismatch_fn
{
    template<std::input_iterator I1, std::sentinel_for<I1> S1,
             std::input_iterator I2, std::sentinel_for<I2> S2,
             class Pred = ranges::equal_to,
             class Proj1 = std::identity, class Proj2 = std::identity>
    requires std::indirectly_comparable<I1, I2, Pred, Proj1, Proj2>
    constexpr std::mismatch_result<I1, I2>
        operator()(I1 first1, S1 last1, I2 first2, S2 last2,
                   Pred pred = {}, Proj1 proj1 = {}, Proj2 proj2 = {}) const
    {
        for (; first1 != last1 && first2 != last2; ++first1, (void)++first2)
            if (not std::invoke(pred, std::invoke(proj1, *first1),
                                      std::invoke(proj2, *first2)))
                break;
 
        return {first1, first2};
    }
 
    template<ranges::input_range R1, ranges::input_range R2,
             class Pred = ranges::equal_to,
             class Proj1 = std::identity, class Proj2 = std::identity>
    requires std::indirectly_comparable<ranges::iterator_t<R1>, ranges::iterator_t<R2>,
                                        Pred, Proj1, Proj2>
    constexpr ranges::mismatch_result<ranges::borrowed_iterator_t<R1>,
                                      ranges::borrowed_iterator_t<R2>>
        operator()(R1&& r1, R2&& r2, Pred pred = {},
                   Proj1 proj1 = {}, Proj2 proj2 = {}) const
    {
        return (*this)(ranges::begin(r1), ranges::end(r1),
                       ranges::begin(r2), ranges::end(r2),
                       std::ref(pred), std::ref(proj1), std::ref(proj2));
    }
};
 
inline constexpr mismatch_fn mismatch;
[edit] Example

This program determines the longest substring that is simultaneously found at the very beginning and at the very end of the given string, in reverse order (possibly overlapping).

#include <algorithm>
#include <iostream>
#include <ranges>
#include <string_view>
 
[[nodiscard]]
constexpr std::string_view mirror_ends(const std::string_view in)
{
    const auto end = std::ranges::mismatch(in, in | std::views::reverse).in1;
    return {in.cbegin(), end};
}
 
int main()
{
    std::cout << mirror_ends("abXYZba") << '\n'
              << mirror_ends("abca") << '\n'
              << mirror_ends("ABBA") << '\n'
              << mirror_ends("level") << '\n';
 
    using namespace std::literals::string_view_literals;
 
    static_assert("123"sv == mirror_ends("123!@#321"));
    static_assert("radar"sv == mirror_ends("radar"));
}

Output:

[edit] See also

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