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Showing content from https://en.cppreference.com/w/cpp/language/../language/../algorithm/for_each_n.html below:

std::for_each_n - cppreference.com

template< class InputIt, class Size, class UnaryFunc >
InputIt for_each_n( InputIt first, Size n, UnaryFunc f );

(1) (since C++17)
(constexpr since C++20) template< class ExecutionPolicy,

          class ForwardIt, class Size, class UnaryFunc >
ForwardIt for_each_n( ExecutionPolicy&& policy,

                      ForwardIt first, Size n, UnaryFunc f );
(2) (since C++17)

Applies the given function object f to the result of dereferencing every iterator in the range [firstfirst + n). If f returns a result, the result is ignored.

1) f is applied in order starting from first.

2) f might not be applied in order. The algorithm is executed according to policy.

This overload participates in overload resolution only if all following conditions are satisfied:

If n >= 0 is not true, the behavior is undefined.

If the iterator type (InputIt/ForwardIt) is mutable, f may modify the elements of the range through the dereferenced iterator.

Unlike the rest of the parallel algorithms, for_each_n is not allowed to make copies of the elements in the sequence even if they are TriviallyCopyable.

[edit] Parameters first - the beginning of the range to apply the function to n - the number of elements to apply the function to policy - the execution policy to use f - function object, to be applied to the result of dereferencing every iterator in the range [firstfirst + n)

The signature of the function should be equivalent to the following:

 void fun(const Type &a);

The signature does not need to have const &.
The type  Type must be such that an object of type InputIt can be dereferenced and then implicitly converted to  Type.

​

Type requirements -InputIt must meet the requirements of LegacyInputIterator. -ForwardIt must meet the requirements of LegacyForwardIterator. -Size must be convertible to an integral type. [edit] Return value

An iterator equal to first + n, or more formally, to std::advance(first, n).

[edit] Complexity

Exactly n applications of f.

[edit] Exceptions

The overload with a template parameter named ExecutionPolicy reports errors as follows:

[edit] Possible implementation

See also the implementation in libstdc++, libc++ and MSVC stdlib.

template<class InputIt, class Size, class UnaryFunc>
InputIt for_each_n(InputIt first, Size n, UnaryFunc f)
{
    for (Size i = 0; i < n; ++first, (void) ++i)
        f(*first);
 
    return first;
}
[edit] Example
#include <algorithm>
#include <iostream>
#include <vector>
 
void println(auto const& v)
{
    for (auto count{v.size()}; const auto& e : v)
        std::cout << e << (--count ? ", " : "\n");
}
 
int main()
{
    std::vector<int> vi{1, 2, 3, 4, 5};
    println(vi);
 
    std::for_each_n(vi.begin(), 3, [](auto& n) { n *= 2; });
    println(vi);
}

Output:

1, 2, 3, 4, 5
2, 4, 6, 4, 5
[edit] See also

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