template< class RandomIt >
void stable_sort( RandomIt first, RandomIt last );
void stable_sort( ExecutionPolicy&& policy,
template< class RandomIt, class Compare >
void stable_sort( RandomIt first, RandomIt last, Compare comp );
void stable_sort( ExecutionPolicy&& policy,
Sorts the elements in the range [
first,
last)
in non-descending order. The order of equivalent elements is guaranteed to be preserved.
Elements are
sortedwith respect to
operator<(until C++20)std::less{}(since C++20).
3) Elements are sorted with respect to comp.
2,4) Same as (1,3), but executed according to policy.
These overloads participate in overload resolution only if all following conditions are satisfied:
If any of the following conditions is satisfied, the behavior is undefined:
[edit] Parameters first, last - the pair of iterators defining the range of elements to sort policy - the execution policy to use comp - comparison function object (i.e. an object that satisfies the requirements of Compare) which returns âtrue if the first argument is less than (i.e. is ordered before) the second.The signature of the comparison function should be equivalent to the following:
bool cmp(const Type1& a, const Type2& b);
While the signature does not need to have const&, the function must not modify the objects passed to it and must be able to accept all values of type (possibly const) Type1
and Type2
regardless of value category (thus, Type1&
is not allowed, nor is Type1
unless for Type1
a move is equivalent to a copy(since C++11)).
The types Type1 and Type2 must be such that an object of type RandomIt can be dereferenced and then implicitly converted to both of them. â
RandomIt
must meet the requirements of LegacyRandomAccessIterator. -Compare
must meet the requirements of Compare. [edit] Complexity
Given \(\scriptsize N\)N as last - first:
1,2) \(\scriptsize O(N \cdot \log(N))\)O(N·log(N))comparisons using
operator<(until C++20)std::less{}(since C++20)if enough extra memory is available, otherwise
\(\scriptsize O(N \cdot \log^{2}(N))\)O(N·log2comparisons.
3,4) \(\scriptsize O(N \cdot \log(N))\)O(N·log(N)) applications of the comparator comp if enough extra memory is available, otherwise \(\scriptsize O(N \cdot \log^{2}(N))\)O(N·log2
(N)) applications.
The overloads with a template parameter named ExecutionPolicy
report errors as follows:
ExecutionPolicy
is one of the standard policies, std::terminate is called. For any other ExecutionPolicy
, the behavior is implementation-defined.See also the implementations in libstdc++ and libc++.
[edit] NotesThis function attempts to allocate a temporary buffer equal in size to the sequence to be sorted. If the allocation fails, the less efficient algorithm is chosen.
[edit] Example#include <algorithm> #include <array> #include <iostream> #include <string> #include <vector> struct Employee { int age; std::string name; // Does not participate in comparisons }; bool operator<(const Employee& lhs, const Employee& rhs) { return lhs.age < rhs.age; } #if __cpp_lib_constexpr_algorithms >= 202306L consteval auto get_sorted() { auto v = std::array{3, 1, 4, 1, 5, 9}; std::stable_sort(v.begin(), v.end()); return v; } static_assert(std::ranges::is_sorted(get_sorted())); #endif int main() { std::vector<Employee> v{{108, "Zaphod"}, {32, "Arthur"}, {108, "Ford"}}; std::stable_sort(v.begin(), v.end()); for (const Employee& e : v) std::cout << e.age << ", " << e.name << '\n'; }
Output:
32, Arthur 108, Zaphod 108, Ford[edit] See also sorts a range into ascending order
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