template< class StringViewLike >
void str( const StringViewLike& t );
Manages the contents of the underlying string object.
1) Returns a copy of the underlying string. Equivalent to return rdbuf()->str();.
2) Returns a copy of the underlying string, using a as allocator. Equivalent to return rdbuf()->str(a);.
3) Returns a string move-constructed from the underlying string. Equivalent to return std::move(*rdbuf()).str();.
4,5) Replaces the contents of the underlying string. Equivalent to rdbuf()->str(s);.
6) Replaces the contents of the underlying string. Equivalent to rdbuf()->str(std::move(s));.
7) Replaces the contents of the underlying string. Equivalent to rdbuf()->str(t);.
This overload participates in overload resolution only if is_convertible_v<const T&, basic_string_view<charT, traits>> is true.
[edit] Parameters s - new contents of the underlying string t - an object (convertible to std::basic_string_view) to use as the new contents of the underlying string a - allocator used to construct the returned string [edit] Return value1,2) A copy of the underlying string object.
3) A string move-constructed from the underlying string object.
4-7) (none)
[edit] NotesThe copy of the underlying string returned by str
is a temporary object that will be destructed at the end of the expression, so directly calling c_str() on the result of str() (for example in auto *ptr = out.str().c_str();) results in a dangling pointer.
#include <iostream> #include <sstream> int main() { int n; std::istringstream in; // could also use in("1 2") in.str("1 2"); in >> n; std::cout << "After reading the first int from \"1 2\", the int is " << n << ", str() = \"" << in.str() << "\"\n"; std::ostringstream out("1 2"); out << 3; std::cout << "After writing the int '3' to output stream \"1 2\"" << ", str() = \"" << out.str() << "\"\n"; std::ostringstream ate("1 2", std::ios_base::ate); ate << 3; std::cout << "After writing the int '3' to append stream \"1 2\"" << ", str() = \"" << ate.str() << "\"\n"; }
Output:
After reading the first int from "1 2", the int is 1, str() = "1 2" After writing the int '3' to output stream "1 2", str() = "3 2" After writing the int '3' to append stream "1 2", str() = "1 23"[edit] See also returns the underlying raw string device object
std::basic_stringbuf<CharT,Traits,Allocator>
) [edit]
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