template< class... Types >
class variant;
The class template std::variant
represents a type-safe union.
An instance of variant
at any given time either holds a value of one of its alternative types, or in the case of error - no value (this state is hard to achieve, see valueless_by_exception).
As with unions, if a variant holds a value of some object type T
, the T
object is nested within the variant
object.
A variant is not permitted to hold references, arrays, or the type void.
A variant is permitted to hold the same type more than once, and to hold differently cv-qualified versions of the same type.
Consistent with the behavior of unions during aggregate initialization, a default-constructed variant holds a value of its first alternative, unless that alternative is not default-constructible (in which case the variant is not default-constructible either). The helper class std::monostate can be used to make such variants default-constructible.
A program that instantiates the definition of std::variant
with no template arguments is ill-formed. std::variant<std::monostate> can be used instead.
If a program declares an explicit or partial specialization of std::variant
, the program is ill-formed, no diagnostic required.
variant
object
variant
, along with its contained value
variant
variant
variant
is in the invalid state
variant
, in place
variant
variant
#include <cassert> #include <iostream> #include <string> #include <variant> int main() { std::variant<int, float> v, w; v = 42; // v contains int int i = std::get<int>(v); assert(42 == i); // succeeds w = std::get<int>(v); w = std::get<0>(v); // same effect as the previous line w = v; // same effect as the previous line // std::get<double>(v); // error: no double in [int, float] // std::get<3>(v); // error: valid index values are 0 and 1 try { std::get<float>(w); // w contains int, not float: will throw } catch (const std::bad_variant_access& ex) { std::cout << ex.what() << '\n'; } using namespace std::literals; std::variant<std::string> x("abc"); // converting constructors work when unambiguous x = "def"; // converting assignment also works when unambiguous std::variant<std::string, void const*> y("abc"); // casts to void const* when passed a char const* assert(std::holds_alternative<void const*>(y)); // succeeds y = "xyz"s; assert(std::holds_alternative<std::string>(y)); // succeeds }
Possible output:
std::get: wrong index for variantDefect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR Applied to Behavior as published Correct behavior LWG 2901 C++17 specialization of std::uses_allocator provided,variant
cannot properly support allocators specialization removed LWG 3990 C++17 a program could declare an explicit or
std::variant
the program is ill-formed in this
variant
object See also
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