struct monostate { };
(since C++17)Unit type intended for use as a well-behaved empty alternative in std::variant. In particular, a variant of non-default-constructible types may list std::monostate
as its first alternative: this makes the variant itself default-constructible.
(constructor)
(implicitly declared)
trivial implicit default/copy/move constructor(destructor)
(implicitly declared)
trivial implicit destructoroperator=
(implicitly declared)
trivial implicit copy/move assignmentconstexpr bool operator==( monostate, monostate ) noexcept { return true; }
(1) (since C++17) (2) constexpr bool operator!=( monostate, monostate ) noexcept { return false; }constexpr bool operator< ( monostate, monostate ) noexcept { return false; }
constexpr bool operator> ( monostate, monostate ) noexcept { return false; }
constexpr bool operator<=( monostate, monostate ) noexcept { return true; }
{
return std::strong_ordering::equal;
All instances of std::monostate
compare equal.
The <
, <=
, >
, >=
, and !=
operators are synthesized from operator<=> and operator== respectively.
Specializes the std::hash algorithm for std::monostate
.
#include <cassert> #include <iostream> #include <variant> struct S { S(int i) : i(i) {} int i; }; int main() { // Without the monostate type this declaration will fail. // This is because S is not default-constructible. std::variant<std::monostate, S> var; assert(var.index() == 0); try { std::get<S>(var); // throws! We need to assign a value } catch(const std::bad_variant_access& e) { std::cout << e.what() << '\n'; } var = 42; std::cout << "std::get: " << std::get<S>(var).i << '\n' << "std::hash: " << std::hex << std::showbase << std::hash<std::monostate>{}(std::monostate{}) << '\n'; }
Possible output:
std::get: wrong index for variant std::get: 42 std::hash: 0xffffffffffffe19f[edit] See also
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