double atof( const char* str );
Interprets a floating point value in a byte string pointed to by str.
Function discards any whitespace characters (as determined by std::isspace) until first non-whitespace character is found. Then it takes as many characters as possible to form a valid floating-point representation and converts them to a floating-point value. The valid floating-point value can be one of the following:
e
or E
followed with optional minus or plus sign and nonempty sequence of decimal digits (defines exponent to base 10)0x
or 0X
p
or P
followed with optional minus or plus sign and nonempty sequence of decimal digits (defines exponent to base 2)INF
or INFINITY
ignoring caseNAN
or NAN(
char_sequence )
ignoring case of the NAN
part. char_sequence can only contain digits, Latin letters, and underscores. The result is a quiet NaN floating-point value.double value corresponding to the contents of str on success. If the converted value falls out of range of the return type, the return value is undefined. If no conversion can be performed, 0.0 is returned.
[edit] Example#include <cstdlib> #include <iostream> int main() { std::cout << std::atof("0.0000000123") << '\n' << std::atof("0.012") << '\n' << std::atof("15e16") << '\n' << std::atof("-0x1afp-2") << '\n' << std::atof("inF") << '\n' << std::atof("Nan") << '\n' << std::atof("invalid") << '\n'; }
Output:
1.23e-08 0.012 1.5e+17 -107.75 inf nan 0[edit] See also
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