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Showing content from https://en.cppreference.com/w/cpp/language/../error/error_code/../../numeric/complex/imag2.html below:

std::imag(std::complex) - cppreference.com

(1) (until C++14) template< class T > constexpr T imag( const std::complex<T>& z ); (since C++14) (A) float imag( float f ); double imag( double f ); long double imag( long double f ); (until C++14) constexpr float imag( float f ); constexpr double imag( double f ); constexpr long double imag( long double f ); (since C++14)
(until C++23)

template< class FloatingPoint > FloatingPoint imag( FloatingPoint f );

(since C++23) (B)

template< class Integer > double imag( Integer i );

(until C++14)

template< class Integer > constexpr double imag( Integer i );

(since C++14)

1) Returns the imaginary part of the complex number z, i.e. z.imag().

A,B) Additional overloads are provided for all integer and floating-point types, which are treated as complex numbers with zero imaginary part.

(since C++11) [edit] Parameters z - complex value f - floating-point value i - integer value [edit] Return value

1) The imaginary part of z.

A) decltype(f){} (zero).

B) 0.0.

[edit] Notes

The additional overloads are not required to be provided exactly as (A,B). They only need to be sufficient to ensure that for their argument num:

If num has a standard(until C++23) floating-point type T, then std::imag(num) has the same effect as std::imag(std::complex<T>(num)).
Otherwise, if num has an integer type, then std::imag(num) has the same effect as std::imag(std::complex<double>(num)).

[edit] See also

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