template< class T, unsigned N = 0 >
struct extent;
If T
is an array type, provides the member constant value
equal to the number of elements along the N
th dimension of the array, if N
is in [
â0â,
std::rank<T>::value)
. For any other type, or if T
is an array of unknown bound along its first dimension and N
is â0â, value
is â0â.
If the program adds specializations for std::extent
or std::extent_v
(since C++17), the behavior is undefined.
N
th dimension of T
template<class T, unsigned N = 0> struct extent : std::integral_constant<std::size_t, 0> {}; template<class T> struct extent<T[], 0> : std::integral_constant<std::size_t, 0> {}; template<class T, unsigned N> struct extent<T[], N> : std::extent<T, N - 1> {}; template<class T, std::size_t I> struct extent<T[I], 0> : std::integral_constant<std::size_t, I> {}; template<class T, std::size_t I, unsigned N> struct extent<T[I], N> : std::extent<T, N - 1> {};[edit] Example
#include <type_traits> static_assert( std::extent_v<int[3]> == 3 && // default dimension is 0 std::extent_v<int[3], 0> == 3 && // the same as above std::extent_v<int[3][4], 0> == 3 && std::extent_v<int[3][4], 1> == 4 && std::extent_v<int[3][4], 2> == 0 && std::extent_v<int[]> == 0 ); int main() { const auto ext = std::extent<int['*']>{}; static_assert(ext == 42); // with implicit conversion to std::size_t const int ints[]{1, 2, 3, 4}; static_assert(std::extent_v<decltype(ints)> == 4); // array size [[maybe_unused]] int ary[][3] = {{1, 2, 3}}; // ary[0] is of type reference to 'int[3]', so, the extent // cannot be calculated correctly and it returns 0 static_assert(std::is_same_v<decltype(ary[0]), int(&)[3]>); static_assert(std::extent_v<decltype(ary[0])> == 0); // removing reference gives correct extent value 3 static_assert(std::extent_v<std::remove_cvref_t<decltype(ary[0])>> == 3); }[edit] See also checks if a type is an array type
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