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Showing content from https://en.cppreference.com/w/cpp/language/../error/error_code/../../error/../numeric/math/erf.html below:

std::erf, std::erff, std::erfl - cppreference.com

(1) float       erf ( float num );

double      erf ( double num );

long double erf ( long double num ); (until C++23)

/*floating-point-type*/
            erf ( /*floating-point-type*/ num );

(since C++23)
(constexpr since C++26)

float       erff( float num );

(2) (since C++11)
(constexpr since C++26)

long double erfl( long double num );

(3) (since C++11)
(constexpr since C++26) template< /*math-floating-point*/ V >

constexpr /*deduced-simd-t*/<V>

            erf ( const V& v_num ); (S) (since C++26)

template< class Integer >
double      erf ( Integer num );

(A) (constexpr since C++26) 1-3)

Computes the

error function

of

num

.

The library provides overloads of std::erf for all cv-unqualified floating-point types as the type of the parameter.(since C++23)

A) Additional overloads are provided for all integer types, which are treated as double.

(since C++11) [edit] Parameters num - floating-point or integer value [edit] Return value

If no errors occur, value of the error function of

num

, that is

\(\frac{2}{\sqrt{\pi} }\int_{0}^{num}{e^{-{t^2} }\mathsf{d}t}\)∫num
0e-t2
dt

, is returned.

If a range error occurs due to underflow, the correct result (after rounding), that is

\(\frac{2\cdot num}{\sqrt{\pi} }\)

is returned.

[edit] Error handling

Errors are reported as specified in math_errhandling.

If the implementation supports IEEE floating-point arithmetic (IEC 60559),

[edit] Notes

Underflow is guaranteed if |num| < DBL_MIN * (std::sqrt(π) / 2).

\(\operatorname{erf}(\frac{x}{\sigma \sqrt{2} })\)erf()

is the probability that a measurement whose errors are subject to a normal distribution with standard deviation

\(\sigma\)σ

is less than

\(x\)x

away from the mean value.

The additional overloads are not required to be provided exactly as (A). They only need to be sufficient to ensure that for their argument num of integer type, std::erf(num) has the same effect as std::erf(static_cast<double>(num)).

[edit] Example

The following example calculates the probability that a normal variate is on the interval (x1, x2):

#include <cmath>
#include <iomanip>
#include <iostream>
 
double phi(double x1, double x2)
{
    return (std::erf(x2 / std::sqrt(2)) - std::erf(x1 / std::sqrt(2))) / 2;
}
 
int main()
{
    std::cout << "Normal variate probabilities:\n"
              << std::fixed << std::setprecision(2);
    for (int n = -4; n < 4; ++n)
        std::cout << '[' << std::setw(2) << n
                  << ':' << std::setw(2) << n + 1 << "]: "
                  << std::setw(5) << 100 * phi(n, n + 1) << "%\n";
 
    std::cout << "Special values:\n"
              << "erf(-0) = " << std::erf(-0.0) << '\n'
              << "erf(Inf) = " << std::erf(INFINITY) << '\n';
}

Output:

Normal variate probabilities:
[-4:-3]:  0.13%
[-3:-2]:  2.14%
[-2:-1]: 13.59%
[-1: 0]: 34.13%
[ 0: 1]: 34.13%
[ 1: 2]: 13.59%
[ 2: 3]:  2.14%
[ 3: 4]:  0.13%
Special values:
erf(-0) = -0.00
erf(Inf) = 1.00
[edit] See also [edit] External links

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