template< class T >
constexpr int countl_one( T x ) noexcept;
Returns the number of consecutive 1 (âoneâ) bits in the value of x, starting from the most significant bit (âleftâ).
This overload participates in overload resolution only if T is an unsigned integer type (that is, unsigned char, unsigned short, unsigned int, unsigned long, unsigned long long, or an extended unsigned integer type).
The number of consecutive 1 bits in the value of x, starting from the most significant bit.
[edit] Notes [edit] Example#include <bit>
#include <bitset>
#include <cstdint>
#include <iostream>
int main()
{
for (const std::uint8_t i : {0, 0b11111111, 0b01111111, 0b11100011})
std::cout << "countl_one( " << std::bitset<8>(i) << " ) = "
<< std::countl_one(i) << '\n';
}
Output:
countl_one( 00000000 ) = 0 countl_one( 11111111 ) = 8 countl_one( 01111111 ) = 0 countl_one( 11100011 ) = 3[edit] See also counts the number of consecutive â0â bits, starting from the most significant bit
std::bitset<N>) [edit] checks if all, any or none of the bits are set to true
std::bitset<N>) [edit]
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