template< class T >
struct is_scalar;
std::is_scalar
is a UnaryTypeTrait.
If T
is a scalar type, provides the member constant value
equal true. For any other type, value
is false.
If the program adds specializations for std::is_scalar
or std::is_scalar_v
, the behavior is undefined.
template< class T >
constexpr bool is_scalar_v = is_scalar<T>::value;
T
is a scalar type, false otherwise
Each individual memory location in the C++ memory model, including the hidden memory locations used by language features (e.g. virtual table pointer), has scalar type (or is a sequence of adjacent bit-fields of non-zero length). Sequencing of side-effects in expression evaluation, inter-thread synchronization, and dependency ordering are all defined in terms of individual scalar objects.
[edit] Possible implementation [edit] Example#include <iostream> #include <type_traits> #include <typeinfo> #include <utility> template<typename Head, typename... Tail> void are_scalars(Head&& head, Tail&&... tail) { using T = std::decay_t<decltype(head)>; std::cout << typeid(T).name() << " is " << (std::is_scalar_v<T> ? "" : "not ") << "a scalar\n"; if constexpr (sizeof... (Tail)) { are_scalars(std::forward<decltype(tail)>(tail)...); } } int main() { struct S { int m; } s; int S::* mp = &S::m; enum class E { e }; are_scalars(42, 3.14, E::e, "str", mp, nullptr, s); }
Possible output:
int is a scalar double is a scalar main::E is a scalar char const* is a scalar int main::S::* is a scalar nullptr is a scalar main::S is not a scalar[edit] See also checks if a type is an arithmetic type
RetroSearch is an open source project built by @garambo | Open a GitHub Issue
Search and Browse the WWW like it's 1997 | Search results from DuckDuckGo
HTML:
3.2
| Encoding:
UTF-8
| Version:
0.7.4