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Showing content from https://en.cppreference.com/w/cpp/language/../error/../language/../algorithm/random_shuffle.html below:

std::random_shuffle, std::shuffle - cppreference.com

template< class RandomIt >
void random_shuffle( RandomIt first, RandomIt last );

(1) (deprecated in C++14)
(removed in C++17) (2)

template< class RandomIt, class RandomFunc >
void random_shuffle( RandomIt first, RandomIt last, RandomFunc& r );

(until C++11)

template< class RandomIt, class RandomFunc >
void random_shuffle( RandomIt first, RandomIt last, RandomFunc&& r );

(since C++11)
(deprecated in C++14)
(removed in C++17)

template< class RandomIt, class URBG >
void shuffle( RandomIt first, RandomIt last, URBG&& g );

(3) (since C++11)

Reorders the elements in the given range [firstlast) such that each possible permutation of those elements has equal probability of appearance.

1)

The source of randomness is implementation-defined, but the function

std::rand

is often used.

2) The source of randomness is the function object r.

If any of the following conditions is satisfied, the behavior is undefined:

3) The source of randomness is the object g.

If the type of *first is not Swappable(until C++11)RandomIt is not ValueSwappable(since C++11), the behavior is undefined.

[edit] Parameters first, last - the pair of iterators defining the range of elements to shuffle randomly r - function object returning a randomly chosen value g - generator object returning a randomly chosen value Type requirements -RandomIt must meet the requirements of LegacyRandomAccessIterator. [edit] Complexity

Exactly std::distance(first, last) - 1 swaps.

[edit] Possible implementation

See also the implementations in libstdc++ and libc++.

random_shuffle (1)
template<class RandomIt>
void random_shuffle(RandomIt first, RandomIt last)
{
    typedef typename std::iterator_traits<RandomIt>::difference_type diff_t;
 
    for (diff_t i = last - first - 1; i > 0; --i)
    {
        using std::swap;
        swap(first[i], first[std::rand() % (i + 1)]);
        // rand() % (i + 1) is not actually correct, because the generated number is
        // not uniformly distributed for most values of i. The correct code would be
        // a variation of the C++11 std::uniform_int_distribution implementation.
    }
}
random_shuffle (2)
template<class RandomIt, class RandomFunc>
void random_shuffle(RandomIt first, RandomIt last, RandomFunc&& r)
{
    typedef typename std::iterator_traits<RandomIt>::difference_type diff_t;
 
    for (diff_t i = last - first - 1; i > 0; --i)
    {
        using std::swap;
        swap(first[i], first[r(i + 1)]);
    }
}
shuffle (3)
template<class RandomIt, class URBG>
void shuffle(RandomIt first, RandomIt last, URBG&& g)
{
    typedef typename std::iterator_traits<RandomIt>::difference_type diff_t;
    typedef std::uniform_int_distribution<diff_t> distr_t;
    typedef typename distr_t::param_type param_t;
 
    distr_t D;
    for (diff_t i = last - first - 1; i > 0; --i)
    {
        using std::swap;
        swap(first[i], first[D(g, param_t(0, i))]);
    }
}
[edit] Notes

Note that the implementation is not dictated by the standard, so even if you use exactly the same RandomFunc or URBG (Uniform Random Number Generator) you may get different results with different standard library implementations.

The reason for removing std::random_shuffle in C++17 is that the iterator-only version usually depends on std::rand, which is now also discussed for deprecation. (std::rand should be replaced with the classes of the <random> header, as std::rand is considered harmful.) In addition, the iterator-only std::random_shuffle version usually depends on a global state. The std::shuffle's shuffle algorithm is the preferred replacement, as it uses a URBG as its 3rd parameter.

[edit] Example

Randomly shuffles the sequence [110] of integers:

#include <algorithm>
#include <iostream>
#include <iterator>
#include <random>
#include <vector>
 
int main()
{
    std::vector<int> v{1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
 
    std::random_device rd;
    std::mt19937 g(rd());
 
    std::shuffle(v.begin(), v.end(), g);
 
    std::copy(v.begin(), v.end(), std::ostream_iterator<int>(std::cout, " "));
    std::cout << '\n';
}

Possible output:

[edit] Defect reports

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.

DR Applied to Behavior as published Correct behavior LWG 395 C++98 the source of randomness of overload (1) was not specified, and
std::rand could not be the source due to the C library requirement it is implementation-defined,
and using std::rand is allowed LWG 552
(N2423) C++98 r was not required to be the source
of randomness of overload (2)[1] required
  1. ↑ Overload (3) has the same defect, but that part of the resolution is not applicable to C++98.
[edit] See also generates the next greater lexicographic permutation of a range of elements
(function template) [edit] generates the next smaller lexicographic permutation of a range of elements
(function template) [edit] randomly re-orders elements in a range
(algorithm function object)[edit]

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