#include <complex>
#include <iostream>
#include <numeric>
#include <string_view>
#include <vector>
void println(std::string_view comment, const auto& c)
{
std::cout << comment << '[';
bool first{true};
for (const auto& x : c)
std::cout << (first ? first = false, "" : ", ") << x;
std::cout << "]\n";
}
int main()
{
std::vector<char> cnt(10);
std::iota(cnt.begin(), cnt.end(), '0');
println("Initially, cnt = ", cnt);
std::erase(cnt, '3');
println("After erase '3', cnt = ", cnt);
auto erased = std::erase_if(cnt, [](char x) { return (x - '0') % 2 == 0; });
println("After erase all even numbers, cnt = ", cnt);
std::cout << "Erased even numbers: " << erased << '\n';
std::vector<std::complex<double>> nums{{2, 2}, {4, 2}, {4, 8}, {4, 2}};
#ifdef __cpp_lib_algorithm_default_value_type
std::erase(nums, {4, 2});
#else
std::erase(nums, std::complex<double>{4, 2});
#endif
println("After erase {4, 2}, nums = ", nums);
}
Initially, cnt = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
After erase '3', cnt = [0, 1, 2, 4, 5, 6, 7, 8, 9]
After erase all even numbers, cnt = [1, 5, 7, 9]
Erased even numbers: 5
After erase {4, 2}, nums = [(2,2), (4,8)]
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