iterator end() noexcept;
(1) (since C++11)const_iterator end() const noexcept;
(2) (since C++11)const_iterator cend() const noexcept;
(3) (since C++11)Returns an iterator past the last element of *this.
This returned iterator only acts as a sentinel. It is not guaranteed to be dereferenceable.
[edit] Return valueIterator past the last element.
[edit] ComplexityConstant.
NotesBecause both iterator
and const_iterator
are constant iterators (and may in fact be the same type), it is not possible to mutate the elements of the container through an iterator returned by any of these member functions.
#include <iostream> #include <unordered_set> struct Point { double x, y; }; int main() { Point pts[3] = {{1, 0}, {2, 0}, {3, 0}}; // points is a set containing the addresses of points std::unordered_set<Point*> points = { pts, pts + 1, pts + 2 }; // Change each y-coordinate of (i, 0) from 0 into i^2 and print the point for (auto iter = points.begin(); iter != points.end(); ++iter) { (*iter)->y = ((*iter)->x) * ((*iter)->x); // iter is a pointer-to-Point* std::cout << "(" << (*iter)->x << ", " << (*iter)->y << ") "; } std::cout << '\n'; // Now using the range-based for loop, we increase each y-coordinate by 10 for (Point* i : points) { i->y += 10; std::cout << "(" << i->x << ", " << i->y << ") "; } }
Possible output:
(3, 9) (1, 1) (2, 4) (3, 19) (1, 11) (2, 14)[edit] See also returns an iterator to the beginning
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