template< class T >
struct remove_all_extents;
If T is a multidimensional array of some type X, provides the member typedef type equal to X, otherwise type is T.
If the program adds specializations for std::remove_all_extents, the behavior is undefined.
type the type of the element of T [edit] Helper types
template< class T >
using remove_all_extents_t = typename remove_all_extents<T>::type;
template<class T>
struct remove_all_extents { typedef T type; };
template<class T>
struct remove_all_extents<T[]> {
typedef typename remove_all_extents<T>::type type;
};
template<class T, std::size_t N>
struct remove_all_extents<T[N]> {
typedef typename remove_all_extents<T>::type type;
};[edit] Example
#include <iostream>
#include <type_traits>
#include <typeinfo>
template<class A>
void info(const A&)
{
typedef typename std::remove_all_extents<A>::type Type;
std::cout << "underlying type: " << typeid(Type).name() << '\n';
}
int main()
{
float a0;
float a1[1][2][3];
float a2[1][1][1][1][2];
float* a3;
int a4[3][2];
double a5[2][3];
struct X { int m; } x0[3][3];
info(a0);
info(a1);
info(a2);
info(a3);
info(a4);
info(a5);
info(x0);
}
Possible output:
underlying type: float underlying type: float underlying type: float underlying type: float* underlying type: int underlying type: double underlying type: main::X[edit] See also checks if a type is an array type
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