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Showing content from https://en.cppreference.com/w/cpp/language/../algorithm/../ranges/../iterator/ranges/next.html below:

std::ranges::next - cppreference.com

Return the n^th successor of iterator i.

The function-like entities described on this page are algorithm function objects (informally known as niebloids), that is:

Explicit template argument lists cannot be specified when calling any of them.
None of them are visible to argument-dependent lookup.
When any of them are found by normal unqualified lookup as the name to the left of the function-call operator, argument-dependent lookup is inhibited.

[edit] Parameters i - an iterator n - number of elements to advance bound - sentinel denoting the end of the range i points to [edit] Return value

1) The successor of iterator i.

2) The n^th successor of iterator i.

3) The first iterator equivalent to bound.

4) The n^th successor of iterator i, or the first iterator equivalent to bound, whichever is first.

[edit] Complexity

1) Constant.

[edit] Possible implementation

struct next_fn
{
    template<std::input_or_output_iterator I>
    constexpr I operator()(I i) const
    {
        ++i;
        return i;
    }
 
    template<std::input_or_output_iterator I>
    constexpr I operator()(I i, std::iter_difference_t<I> n) const
    {
        ranges::advance(i, n);
        return i;
    }
 
    template<std::input_or_output_iterator I, std::sentinel_for<I> S>
    constexpr I operator()(I i, S bound) const
    {
        ranges::advance(i, bound);
        return i;
    }
 
    template<std::input_or_output_iterator I, std::sentinel_for<I> S>
    constexpr I operator()(I i, std::iter_difference_t<I> n, S bound) const
    {
        ranges::advance(i, n, bound);
        return i;
    }
};
 
inline constexpr auto next = next_fn();

[edit] Notes

Although the expression ++x.begin() often compiles, it is not guaranteed to do so: x.begin() is an rvalue expression, and there is no requirement that specifies that increment of an rvalue is guaranteed to work. In particular, when iterators are implemented as pointers or its operator++ is lvalue-ref-qualified, ++x.begin() does not compile, while ranges::next(x.begin()) does.

[edit] Example

#include <cassert>
#include <iterator>
 
int main() 
{
    auto v = {3, 1, 4};
    {
        auto n = std::ranges::next(v.begin());
        assert(*n == 1);
    }
    {
        auto n = std::ranges::next(v.begin(), 2);
        assert(*n == 4);
    }
    {
        auto n = std::ranges::next(v.begin(), v.end());
        assert(n == v.end());
    }
    {
        auto n = std::ranges::next(v.begin(), 42, v.end());
        assert(n == v.end());
    }
}

[edit] See also decrement an iterator by a given distance or to a bound
(algorithm function object)[edit] advances an iterator by given distance or to a given bound
(algorithm function object)[edit] increment an iterator
(function template) [edit]

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