ForwardIt search_n( ForwardIt first, ForwardIt last,
class T = typename std::iterator_traits
<ForwardIt>::value_type >
constexpr ForwardIt search_n( ForwardIt first, ForwardIt last,
class ForwardIt, class Size, class T >
ForwardIt search_n( ExecutionPolicy&& policy,
ForwardIt first, ForwardIt last,
class ForwardIt, class Size,
class T = typename std::iterator_traits
<ForwardIt>::value_type >
ForwardIt search_n( ExecutionPolicy&& policy,
ForwardIt first, ForwardIt last,
ForwardIt search_n( ForwardIt first, ForwardIt last,
class T = typename std::iterator_traits
<ForwardIt>::value_type,
class BinaryPred >
constexpr ForwardIt search_n( ForwardIt first, ForwardIt last,
class T, class BinaryPred >
ForwardIt search_n( ExecutionPolicy&& policy,
ForwardIt first, ForwardIt last,
class T = typename std::iterator_traits
<ForwardIt>::value_type,
class BinaryPred >
ForwardIt search_n( ExecutionPolicy&& policy,
ForwardIt first, ForwardIt last,
Searches the range [
first,
last)
for the first sequence of count identical elements, each equal to the given value.
1) Elements are compared using operator==.
3) Elements are compared using the given binary predicate p.
2,4) Same as (1,3), but executed according to policy.
These overloads participate in overload resolution only if all following conditions are satisfied:
[edit] Parameters first, last - the pair of iterators defining the range of elements to examine count - the length of the sequence to search for value - the value of the elements to search for policy - the execution policy to use p - binary predicate which returns âtrue if the elements should be treated as equal.The signature of the predicate function should be equivalent to the following:
bool pred(const Type1 &a, const Type2 &b);
While the signature does not need to have const &, the function must not modify the objects passed to it and must be able to accept all values of type (possibly const) Type1
and Type2
regardless of value category (thus, Type1 & is not allowed, nor is Type1 unless for Type1
a move is equivalent to a copy(since C++11)).
The type Type1 must be such that an object of type ForwardIt can be dereferenced and then implicitly converted to Type1. The type Type2 must be such that an object of type T can be implicitly converted to Type2. â
ForwardIt
must meet the requirements of LegacyForwardIterator. -BinaryPred
must meet the requirements of BinaryPredicate. -Size
must be convertible to an integral type. [edit] Return value
If count is positive, returns an iterator to the beginning of the first sequence found in the range [
first,
last)
. Each iterator it in the sequence should satisfy the following condition:
1,2) *it == value is true.
3,4) p(*it, value) != false is true.
If no such sequence is found, last is returned.
If count is zero or negative, first is returned.
[edit] ComplexityGiven \(\scriptsize N\)N as std::distance(first, last):
1,2) At most \(\scriptsize N\)N comparisons using operator==.
3,4) At most \(\scriptsize N\)N applications of the predicate p.
[edit] ExceptionsThe overloads with a template parameter named ExecutionPolicy
report errors as follows:
ExecutionPolicy
is one of the standard policies, std::terminate is called. For any other ExecutionPolicy
, the behavior is implementation-defined.template<class ForwardIt, class Size, class T = typename std::iterator_traits<ForwardIt>::value_type> ForwardIt search_n(ForwardIt first, ForwardIt last, Size count, const T& value) { if (count <= 0) return first; for (; first != last; ++first) { if (!(*first == value)) continue; ForwardIt candidate = first; for (Size cur_count = 1; true; ++cur_count) { if (cur_count >= count) return candidate; // success ++first; if (first == last) return last; // exhausted the list if (!(*first == value)) break; // too few in a row } } return last; }search_n (3)
template<class ForwardIt, class Size, class T = typename std::iterator_traits<ForwardIt>::value_type, class BinaryPred> ForwardIt search_n(ForwardIt first, ForwardIt last, Size count, const T& value, BinaryPred p) { if (count <= 0) return first; for (; first != last; ++first) { if (!p(*first, value)) continue; ForwardIt candidate = first; for (Size cur_count = 1; true; ++cur_count) { if (cur_count >= count) return candidate; // success ++first; if (first == last) return last; // exhausted the list if (!p(*first, value)) break; // too few in a row } } return last; }[edit] Notes [edit] Example
#include <algorithm> #include <cassert> #include <complex> #include <iostream> #include <iterator> #include <vector> template<class Container, class Size, class T> constexpr bool consecutive_values(const Container& c, Size count, const T& v) { return std::search_n(std::begin(c), std::end(c), count, v) != std::end(c); } int main() { constexpr char sequence[] = ".0_0.000.0_0."; static_assert(consecutive_values(sequence, 3, '0')); for (int n : {4, 3, 2}) std::cout << std::boolalpha << "Has " << n << " consecutive zeros: " << consecutive_values(sequence, n, '0') << '\n'; std::vector<std::complex<double>> nums{{4, 2}, {4, 2}, {1, 3}}; #ifdef __cpp_lib_algorithm_default_value_type auto it = std::search_n(nums.cbegin(), nums.cend(), 2, {4, 2}); #else auto it = std::search_n(nums.cbegin(), nums.cend(), 2, std::complex<double>{4, 2}); #endif assert(it == nums.begin()); }
Output:
Has 4 consecutive zeros: false Has 3 consecutive zeros: true Has 2 consecutive zeros: true[edit] Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR Applied to Behavior as published Correct behavior LWG 283 C++98T
was required to be EqualityComparable, but
InputIt
is not always T
removed the requirement LWG 426 C++98 the complexity upper limit was N·count
,
N·count
, but in
N
changed the upper
N
in this case LWG 2150 C++98 the condition of âsequence occurenceâ was incorrect corrected [edit] See also finds the last sequence of elements in a certain range
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