double ellint_2 ( double k, double phi );
/* floating-point-type */ ellint_2( /* floating-point-type */ k,
/* floating-point-type */ phi );
float ellint_2f( float k, float phi );
(2) (since C++17)long double ellint_2l( long double k, long double phi );
(3) (since C++17) template< class Arithmetic1, class Arithmetic2 >/* common-floating-point-type */
A) Additional overloads are provided for all other combinations of arithmetic types.
[edit] Parameters k - elliptic modulus or eccentricity (a floating-point or integer value) phi - Jacobi amplitude (a floating-point or integer value, measured in radians) [edit] Return valueIf no errors occur, value of the incomplete elliptic integral of the second kind of k and phi, that is ∫phi
0â1-k2
sin2
θdθ, is returned.
Errors may be reported as specified in math_errhandling:
Implementations that do not support C++17, but support ISO 29124:2010, provide this function if __STDCPP_MATH_SPEC_FUNCS__
is defined by the implementation to a value at least 201003L and if the user defines __STDCPP_WANT_MATH_SPEC_FUNCS__
before including any standard library headers.
Implementations that do not support ISO 29124:2010 but support TR 19768:2007 (TR1), provide this function in the header tr1/cmath
and namespace std::tr1
.
An implementation of this function is also available in boost.math.
The additional overloads are not required to be provided exactly as (A). They only need to be sufficient to ensure that for their first argument num1 and second argument num2:
If num1 and num2 have arithmetic types, then std::ellint2(num1, num2) has the same effect as std::ellint2(static_cast</* common-floating-point-type */>(num1),
static_cast</* common-floating-point-type */>(num2)), where /* common-floating-point-type */ is the floating-point type with the greatest floating-point conversion rank and greatest floating-point conversion subrank between the types of num1 and num2, arguments of integer type are considered to have the same floating-point conversion rank as double.
If no such floating-point type with the greatest rank and subrank exists, then overload resolution does not result in a usable candidate from the overloads provided.
(since C++23) [edit] Example#include <cmath> #include <iostream> #include <numbers> int main() { const double hpi = std::numbers::pi / 2.0; std::cout << "E(0,Ï/2) = " << std::ellint_2(0, hpi) << '\n' << "E(0,-Ï/2) = " << std::ellint_2(0, -hpi) << '\n' << "Ï/2 = " << hpi << '\n' << "E(0.7,0) = " << std::ellint_2(0.7, 0) << '\n' << "E(1,Ï/2) = " << std::ellint_2(1, hpi) << '\n'; }
Output:
E(0,Ï/2) = 1.5708 E(0,-Ï/2) = -1.5708 Ï/2 = 1.5708 E(0.7,0) = 0 E(1,Ï/2) = 1[edit] See also [edit] External links
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