double floor ( double num );
constexpr /*floating-point-type*/
floor ( /*floating-point-type*/ num );
float floorf( float num );
(2) (since C++11)long double floorl( long double num );
(3) (since C++11)constexpr /*deduced-simd-t*/<V>
template< class Integer >
double floor ( Integer num );
1-3) Computes the largest integer value not greater than num. The library provides overloads of std::floor
for all cv-unqualified floating-point types as the type of the parameter.(since C++23)
A) Additional overloads are provided for all integer types, which are treated as double.
(since C++11) [edit] Parameters num - floating-point or integer value [edit] Return valueIf no errors occur, the largest integer value not greater than num, that is ânumâ, is returned.
Return value
num
[edit] Error handlingErrors are reported as specified in math_errhandling.
If the implementation supports IEEE floating-point arithmetic (IEC 60559),
FE_INEXACT may be (but isn't required to be) raised when rounding a non-integer finite value.
The largest representable floating-point values are exact integers in all standard floating-point formats, so this function never overflows on its own; however the result may overflow any integer type (including std::intmax_t), when stored in an integer variable.
The additional overloads are not required to be provided exactly as (A). They only need to be sufficient to ensure that for their argument num of integer type, std::floor(num) has the same effect as std::floor(static_cast<double>(num)).
[edit] Example#include <cmath> #include <iostream> int main() { std::cout << std::fixed << "floor(+2.7) = " << std::floor(+2.7) << '\n' << "floor(-2.7) = " << std::floor(-2.7) << '\n' << "floor(-0.0) = " << std::floor(-0.0) << '\n' << "floor(-Inf) = " << std::floor(-INFINITY) << '\n'; }
Output:
floor(+2.7) = 2.000000 floor(-2.7) = -3.000000 floor(-0.0) = -0.000000 floor(-Inf) = -inf[edit] See also
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