concept common_with =
std::same_as<std::common_type_t<T, U>, std::common_type_t<U, T>> &&
requires {
static_cast<std::common_type_t<T, U>>(std::declval<T>());
static_cast<std::common_type_t<T, U>>(std::declval<U>());
} &&
std::common_reference_with<
std::add_lvalue_reference_t<const T>,
std::add_lvalue_reference_t<const U>> &&
std::common_reference_with<
std::add_lvalue_reference_t<std::common_type_t<T, U>>,
std::common_reference_t<
std::add_lvalue_reference_t<const T>,
The concept common_with<T, U>
specifies that two types T
and U
share a common type (as computed by std::common_type_t) to which both can be converted.
T and U model std::common_with<T, U> only if, given equality-preserving expressions t1
, t2
, u1
and u2
such that decltype((t1)) and decltype((t2)) are both T
and decltype((u1)) and decltype((u2)) are both U
,
t1
equals t2
; andu1
equals u2
.In other words, the conversion to the common type must preserve equality.
[edit] Equality preservationExpressions declared in requires expressions of the standard library concepts are required to be equality-preserving (except where stated otherwise).
[edit] Referencescommon_with
[concept.common]common_with
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