Call signature
(1) (since C++20) (2) (since C++20)Examines the range [
first,
last)
and finds the largest range beginning at first in which the elements are sorted in non-descending order.
A sequence is sorted with respect to a comparator comp if for any iterator it
pointing to the sequence and any non-negative integer n
such that it + n
is a valid iterator pointing to an element of the sequence, std::invoke(comp, std::invoke(proj, *(it + n)), std::invoke(proj, *it)) evaluates to false.
1) Elements are compared using the given binary comparison function comp.
The function-like entities described on this page are algorithm function objects (informally known as niebloids), that is:
The upper bound of the largest range beginning at first in which the elements are sorted in non-descending order. That is, the last iterator it
for which range [
first,
it)
is sorted.
Linear in the distance between first and last.
[edit] Possible implementationstruct is_sorted_until_fn { template<std::forward_iterator I, std::sentinel_for<I> S, class Proj = std::identity, std::indirect_strict_weak_order<std::projected<I, Proj>> Comp = ranges::less> constexpr I operator()(I first, S last, Comp comp = {}, Proj proj = {}) const { if (first == last) return first; for (auto next = first; ++next != last; first = next) if (std::invoke(comp, std::invoke(proj, *next), std::invoke(proj, *first))) return next; return first; } template<ranges::forward_range R, class Proj = std::identity, std::indirect_strict_weak_order< std::projected<ranges::iterator_t<R>, Proj>> Comp = ranges::less> constexpr ranges::borrowed_iterator_t<R> operator()(R&& r, Comp comp = {}, Proj proj = {}) const { return (*this)(ranges::begin(r), ranges::end(r), std::ref(comp), std::ref(proj)); } }; inline constexpr is_sorted_until_fn is_sorted_until;[edit] Notes
ranges::is_sorted_until
returns an iterator equal to last for empty ranges and ranges of length one.
Possible output:
4 1 9 5 1 3 : 1 leading sorted element(s) 4 5 9 3 1 1 : 3 leading sorted element(s) 9 3 1 4 5 1 : 1 leading sorted element(s) 1 3 5 4 1 9 : 3 leading sorted element(s) 5 9 1 1 3 4 : 2 leading sorted element(s) 4 9 1 5 1 3 : 2 leading sorted element(s) 1 1 4 9 5 3 : 4 leading sorted element(s)[edit] See also
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