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Showing content from https://en.cppreference.com/w/cpp/language/../algorithm/../algorithm/none_of.html below:

std::all_of, std::any_of, std::none_of - cppreference.com

template< class InputIt, class UnaryPred >
bool all_of( InputIt first, InputIt last, UnaryPred p );

(1) (since C++11)
(constexpr since C++20) template< class ExecutionPolicy, class ForwardIt, class UnaryPred >

bool all_of( ExecutionPolicy&& policy,

             ForwardIt first, ForwardIt last, UnaryPred p );
(2) (since C++17)

template< class InputIt, class UnaryPred >
bool any_of( InputIt first, InputIt last, UnaryPred p );

(3) (since C++11)
(constexpr since C++20) template< class ExecutionPolicy, class ForwardIt, class UnaryPred >

bool any_of( ExecutionPolicy&& policy,

             ForwardIt first, ForwardIt last, UnaryPred p );
(4) (since C++17)

template< class InputIt, class UnaryPred >
bool none_of( InputIt first, InputIt last, UnaryPred p );

(5) (since C++11)
(constexpr since C++20) template< class ExecutionPolicy, class ForwardIt, class UnaryPred >

bool none_of( ExecutionPolicy&& policy,

              ForwardIt first, ForwardIt last, UnaryPred p );
(6) (since C++17)

1) Checks if unary predicate p returns true for all elements in the range [firstlast).

3) Checks if unary predicate p returns true for at least one element in the range [firstlast).

5) Checks if unary predicate p returns true for none of the elements in the range [firstlast).

2,4,6) Same as (1,3,5), but executed according to policy.

These overloads participate in overload resolution only if all following conditions are satisfied:

[edit] Parameters first, last - the pair of iterators defining the range of elements to examine policy - the execution policy to use p - unary predicate .

The expression p(v) must be convertible to bool for every argument v of type (possibly const) VT, where VT is the value type of InputIt, regardless of value category, and must not modify v. Thus, a parameter type of VT&is not allowed, nor is VT unless for VT a move is equivalent to a copy(since C++11). ​

Type requirements -InputIt must meet the requirements of LegacyInputIterator. -ForwardIt must meet the requirements of LegacyForwardIterator. -UnaryPred must meet the requirements of Predicate. [edit] Return value Range has some true element Yes No  Range has some false element  Yes No Yes     No[1] all_of false true false true any_of true true   false     false   none_of   false     false   true true
  1. ↑ The range is empty in this case.
[edit] Complexity 1-6)

At most

std::distance(first, last)

applications of the predicate

p

.

[edit] Exceptions

The overloads with a template parameter named ExecutionPolicy report errors as follows:

[edit] Possible implementation

See also the implementations of

all_of
template<class InputIt, class UnaryPred>
constexpr bool all_of(InputIt first, InputIt last, UnaryPred p)
{
    return std::find_if_not(first, last, p) == last;
}
any_of
template<class InputIt, class UnaryPred>
constexpr bool any_of(InputIt first, InputIt last, UnaryPred p)
{
    return std::find_if(first, last, p) != last;
}
none_of
template<class InputIt, class UnaryPred>
constexpr bool none_of(InputIt first, InputIt last, UnaryPred p)
{
    return std::find_if(first, last, p) == last;
}
[edit] Example
#include <algorithm>
#include <functional>
#include <iostream>
#include <iterator>
#include <numeric>
#include <vector>
 
int main()
{
    std::vector<int> v(10, 2);
    std::partial_sum(v.cbegin(), v.cend(), v.begin());
    std::cout << "Among the numbers: ";
    std::copy(v.cbegin(), v.cend(), std::ostream_iterator<int>(std::cout, " "));
    std::cout << '\n';
 
    if (std::all_of(v.cbegin(), v.cend(), [](int i) { return i % 2 == 0; }))
        std::cout << "All numbers are even\n";
 
    if (std::none_of(v.cbegin(), v.cend(), std::bind(std::modulus<>(),
                                                     std::placeholders::_1, 2)))
        std::cout << "None of them are odd\n";
 
    struct DivisibleBy
    {
        const int d;
        DivisibleBy(int n) : d(n) {}
        bool operator()(int n) const { return n % d == 0; }
    };
 
    if (std::any_of(v.cbegin(), v.cend(), DivisibleBy(7)))
        std::cout << "At least one number is divisible by 7\n";
}

Output:

Among the numbers: 2 4 6 8 10 12 14 16 18 20
All numbers are even
None of them are odd
At least one number is divisible by 7
[edit] See also

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