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Showing content from https://en.cppreference.com/w/cpp/language/../algorithm/../../cpp/../c/numeric/math/log2.html below:

log2, log2f, log2l - cppreference.com

float       log2f( float arg );

(1) (since C99)

double      log2( double arg );

(2) (since C99)

long double log2l( long double arg );

(3) (since C99)

#define log2( arg )

(4) (since C99)

1-3) Computes the base 2 logarithm of arg.

4) Type-generic macro: If arg has type long double, log2l is called. Otherwise, if arg has integer type or the type double, log2 is called. Otherwise, log2f is called.

[edit] Parameters arg - floating point value [edit] Return value

If no errors occur, the base-2 logarithm of arg (log2(arg) or lb(arg)) is returned.

If a domain error occurs, an implementation-defined value is returned (NaN where supported).

If a pole error occurs, -HUGE_VAL, -HUGE_VALF, or -HUGE_VALL is returned.

[edit] Error handling

Errors are reported as specified in math_errhandling.

Domain error occurs if arg is less than zero.

Pole error may occur if arg is zero.

If the implementation supports IEEE floating-point arithmetic (IEC 60559),

[edit] Notes

For integer arg, the binary logarithm can be interpreted as the zero-based index of the most significant 1 bit in the input.

[edit] Example
#include <stdio.h>
#include <math.h>
#include <float.h>
#include <errno.h>
#include <fenv.h>
// #pragma STDC FENV_ACCESS ON
int main(void)
{
    printf("log2(65536) = %f\n", log2(65536));
    printf("log2(0.125) = %f\n", log2(0.125));
    printf("log2(0x020f) = %f (highest set bit is in position 9)\n", log2(0x020f));
    printf("base-5 logarithm of 125 = %f\n", log2(125)/log2(5));
    // special values
    printf("log2(1) = %f\n", log2(1));
    printf("log2(+Inf) = %f\n", log2(INFINITY));
    //error handling
    errno = 0; feclearexcept(FE_ALL_EXCEPT);
    printf("log2(0) = %f\n", log2(0));
    if(errno == ERANGE) perror("    errno == ERANGE");
    if(fetestexcept(FE_DIVBYZERO)) puts("    FE_DIVBYZERO raised");
}

Possible output:

log2(65536) = 16.000000
log2(0.125) = -3.000000
log2(0x020f) = 9.041659 (highest set bit is in position 9)
base-5 logarithm of 125 = 3.000000
log2(1) = 0.000000
log2(+Inf) = inf
log2(0) = -inf
    errno == ERANGE: Numerical result out of range
    FE_DIVBYZERO raised
[edit] References
[edit] See also computes natural (base-e) logarithm (\({\small \ln{x} }\)ln(x))
(function) [edit] computes common (base-10) logarithm (\({\small \log_{10}{x} }\)log10(x))
(function) [edit] computes natural (base-e) logarithm of 1 plus the given number (\({\small \ln{(1+x)} }\)ln(1+x))
(function) [edit] computes 2 raised to the given power (\({\small 2^x}\)2x)
(function) [edit]

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