float fmaxf( float x, float y );
(1) (since C99)double fmax( double x, double y );
(2) (since C99)long double fmaxl( long double x, long double y );
(3) (since C99)#define fmax( x, y )
(4) (since C99)1-3) Returns the larger of two floating-point arguments, treating NaNs as missing data (between a NaN and a numeric value, the numeric value is chosen).
4) Type-generic macro: If any argument has type long double, fmaxl is called. Otherwise, if any argument has integer type or has type double, fmax is called. Otherwise, fmaxf is called.
If successful, returns the larger of two floating-point values. The value returned is exact and does not depend on any rounding modes.
[edit] Error handlingThis function is not subject to any of the error conditions specified in math_errhandling.
If the implementation supports IEEE floating-point arithmetic (IEC 60559),
This function is not required to be sensitive to the sign of zero, although some implementations additionally enforce that if one argument is +0 and the other is -0, then +0 is returned.
[edit] Example#include <math.h>
#include <stdio.h>
int main(void)
{
printf("fmax(2,1) = %f\n", fmax(2,1));
printf("fmax(-Inf,0) = %f\n", fmax(-INFINITY,0));
printf("fmax(NaN,-1) = %f\n", fmax(NAN,-1));
}
Output:
fmax(2,1) = 2.000000 fmax(-Inf,0) = 0.000000 fmax(NaN,-1) = -1.000000[edit] References
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