Call signature
(1) (since C++20) (2) (since C++20) template< std::input_iterator I, std::sentinel_for<I> S, std::weakly_incrementable O, class Proj = std::identity,
std::indirect_unary_predicate<std::projected<I, Proj>> Pred >
requires std::indirectly_copyable<I, O>
constexpr copy_if_result<I, O>
Helper types
(5) (since C++20) (6) (since C++20)Copies the elements in the range, defined by [
first,
last)
, to another range beginning at result.
Copies all elements in the range
[
first,
last)
starting from
firstand proceeding to
last - 1. The behavior is undefined if
resultis within the range
[
first,
last)
. In this case,
ranges::copy_backwardmay be used instead.
3) Only copies the elements for which the predicate pred returns true. The relative order of the elements that are copied is preserved. The behavior is undefined if the source and the destination ranges overlap.
The function-like entities described on this page are algorithm function objects (informally known as niebloids), that is:
A ranges::in_out_result containing an input iterator equal to last and an output iterator past the last element copied.
[edit] Complexity1,2) Exactly last - first assignments.
3,4) Exactly last - first applications of the predicate and projection, between â0â and last - first assignments (assignment for every element for which predicate returns true, dependent on predicate and input data).
[edit] NotesIn practice, implementations of ranges::copy
avoid multiple assignments and use bulk copy functions such as std::memmove if the value type is TriviallyCopyable and the iterator types satisfy contiguous_iterator
.
When copying overlapping ranges, ranges::copy
is appropriate when copying to the left (beginning of the destination range is outside the source range) while ranges::copy_backward
is appropriate when copying to the right (end of the destination range is outside the source range).
struct copy_fn { template<std::input_iterator I, std::sentinel_for<I> S, std::weakly_incrementable O> requires std::indirectly_copyable<I, O> constexpr ranges::copy_result<I, O> operator()(I first, S last, O result) const { for (; first != last; ++first, (void)++result) *result = *first; return {std::move(first), std::move(result)}; } template<ranges::input_range R, std::weakly_incrementable O> requires std::indirectly_copyable<ranges::iterator_t<R>, O> constexpr ranges::copy_result<ranges::borrowed_iterator_t<R>, O> operator()(R&& r, O result) const { return (*this)(ranges::begin(r), ranges::end(r), std::move(result)); } }; inline constexpr copy_fn copy;copy_if (3)(4)
struct copy_if_fn { template<std::input_iterator I, std::sentinel_for<I> S, std::weakly_incrementable O, class Proj = std::identity, std::indirect_unary_predicate<std::projected<I, Proj>> Pred> requires std::indirectly_copyable<I, O> constexpr ranges::copy_if_result<I, O> operator()(I first, S last, O result, Pred pred, Proj proj = {}) const { for (; first != last; ++first) if (std::invoke(pred, std::invoke(proj, *first))) { *result = *first; ++result; } return {std::move(first), std::move(result)}; } template<ranges::input_range R, std::weakly_incrementable O, class Proj = std::identity, std::indirect_unary_predicate< std::projected<ranges::iterator_t<R>, Proj>> Pred> requires std::indirectly_copyable<ranges::iterator_t<R>, O> constexpr ranges::copy_if_result<ranges::borrowed_iterator_t<R>, O> operator()(R&& r, O result, Pred pred, Proj proj = {}) const { return (*this)(ranges::begin(r), ranges::end(r), std::move(result), std::ref(pred), std::ref(proj)); } }; inline constexpr copy_if_fn copy_if;[edit] Example
The following code uses ranges::copy
to both copy the contents of one std::vector to another and to display the resulting std::vector
.
#include <algorithm> #include <iostream> #include <iterator> #include <numeric> #include <vector> int main() { std::vector<int> source(10); std::iota(source.begin(), source.end(), 0); std::vector<int> destination; std::ranges::copy(source.begin(), source.end(), std::back_inserter(destination)); // or, alternatively, // std::vector<int> destination(source.size()); // std::ranges::copy(source.begin(), source.end(), destination.begin()); // either way is equivalent to // std::vector<int> destination = source; std::cout << "Destination contains: "; std::ranges::copy(destination, std::ostream_iterator<int>(std::cout, " ")); std::cout << '\n'; std::cout << "Odd numbers in destination are: "; std::ranges::copy_if(destination, std::ostream_iterator<int>(std::cout, " "), [](int x) { return (x % 2) == 1; }); std::cout << '\n'; }
Output:
Destination contains: 0 1 2 3 4 5 6 7 8 9 Odd numbers in destination are: 1 3 5 7 9[edit] See also
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