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std::partial_sum - cppreference.com

template< class InputIt, class OutputIt >

OutputIt partial_sum( InputIt first, InputIt last,

                      OutputIt d_first );
(1) (constexpr since C++20) template< class InputIt, class OutputIt, class BinaryOp >

OutputIt partial_sum( InputIt first, InputIt last,

                      OutputIt d_first, BinaryOp op );
(2) (constexpr since C++20)

1) If [firstlast) is empty, does nothing.

Otherwise, performs the following operations in order:

  1. Creates an accumulator acc, whose type is the value type of InputIt, and initializes it with *first.
  2. Assigns acc to *d_first.
  3. For each integer i in [1std::distance(first, last)), performs the following operations in order:

a) Computes acc + *iter(until C++20)std::move(acc) + *iter(since C++20), where iter is the next ith iterator of first.

b) Assigns the result to acc.

c)

Assigns

acc[1]

to

*dest

, where

dest

is the next

ith

iterator of

d_first

.

2) Same as (1), but computes op(acc, *iter)(until C++20)op(std::move(acc), *iter)(since C++20) instead.

Given binary_op as the actual binary operation:

  1. ↑ The actual value to be assigned is the result of the assignment in the previous step. We assume the assignment result is acc here.
[edit] Parameters first, last - the pair of iterators defining the range of elements to sum d_first - the beginning of the destination range; may be equal to first op - binary operation function object that will be applied.

The signature of the function should be equivalent to the following:

 Ret fun(const Type1 &a, const Type2 &b);

The signature does not need to have const &.
The type  Type1 must be such that an object of type std::iterator_traits<InputIt>::value_type can be implicitly converted to  Type1. The type  Type2 must be such that an object of type InputIt can be dereferenced and then implicitly converted to  Type2. The type Ret must be such that an object of type InputIt can be dereferenced and assigned a value of type Ret. ​

Type requirements -InputIt must meet the requirements of LegacyInputIterator. -OutputIt must meet the requirements of LegacyOutputIterator. [edit] Return value

Iterator to the element past the last element written, or d_first if [firstlast) is empty.

[edit] Complexity

Given \(\scriptsize N\)N as std::distance(first, last):

1) Exactly \(\scriptsize N-1\)N-1 applications of operator+.

2) Exactly \(\scriptsize N-1\)N-1 applications of the binary function op.

[edit] Possible implementation partial_sum (1)
template<class InputIt, class OutputIt>
constexpr // since C++20
OutputIt partial_sum(InputIt first, InputIt last, OutputIt d_first)
{
    if (first == last)
        return d_first;
 
    typename std::iterator_traits<InputIt>::value_type sum = *first;
    *d_first = sum;
 
    while (++first != last)
    {
        sum = std::move(sum) + *first; // std::move since C++20
        *++d_first = sum;
    }
 
    return ++d_first;
 
    // or, since C++14:
    // return std::partial_sum(first, last, d_first, std::plus<>());
}
partial_sum (2)
template<class InputIt, class OutputIt, class BinaryOp>
constexpr // since C++20
OutputIt partial_sum(InputIt first, InputIt last, 
                     OutputIt d_first, BinaryOp op)
{
    if (first == last)
        return d_first;
 
    typename std::iterator_traits<InputIt>::value_type acc = *first;
    *d_first = acc;
 
    while (++first != last)
    {
        acc = op(std::move(acc), *first); // std::move since C++20
        *++d_first = acc;
    }
 
    return ++d_first;
}
[edit] Notes

acc was introduced because of the resolution of LWG issue 539. The reason of using acc rather than directly summing up the results (i.e. *(d_first + 2) = (*first + *(first + 1)) + *(first + 2);) is because the semantic of the latter is confusing if the following types mismatch:

acc serves as the intermediate object to store and provide the values for each step of the computation:

enum not_int { x = 1, y = 2 };
 
char i_array[4] = {100, 100, 100, 100};
not_int e_array[4] = {x, x, y, y};
int  o_array[4];
 
// OK: uses operator+(char, char) and assigns char values to int array
std::partial_sum(i_array, i_array + 4, o_array);
 
// Error: cannot assign not_int values to int array
std::partial_sum(e_array, e_array + 4, o_array);
 
// OK: performs conversions when needed
// 1. creates “acc” of type char (the value type)
// 2. the char arguments are used for long multiplication (char -> long)
// 3. the long product is assigned to “acc” (long -> char)
// 4. “acc” is assigned to an element of “o_array” (char -> int)
// 5. go back to step 2 to process the remaining elements in the input range
std::partial_sum(i_array, i_array + 4, o_array, std::multiplies<long>{});
[edit] Example
#include <functional>
#include <iostream>
#include <iterator>
#include <numeric>
#include <vector>
 
int main()
{
    std::vector<int> v(10, 2); // v = {2, 2, 2, 2, 2, 2, 2, 2, 2, 2}
 
    std::cout << "The first " << v.size() << " even numbers are: ";
    // write the result to the cout stream
    std::partial_sum(v.cbegin(), v.cend(), 
                     std::ostream_iterator<int>(std::cout, " "));
    std::cout << '\n';
 
    // write the result back to the vector v
    std::partial_sum(v.cbegin(), v.cend(),
                     v.begin(), std::multiplies<int>());
 
    std::cout << "The first " << v.size() << " powers of 2 are: ";
    for (int n : v)
        std::cout << n << ' ';
    std::cout << '\n';
}

Output:

The first 10 even numbers are: 2 4 6 8 10 12 14 16 18 20 
The first 10 powers of 2 are: 2 4 8 16 32 64 128 256 512 1024
[edit] Defect reports

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.

DR Applied to Behavior as published Correct behavior LWG 242 C++98 op could not have side effects it cannot modify the ranges involved LWG 539 C++98 the type requirements needed for the result
evaluations and assignments to be valid were missing added [edit] See also computes the differences between adjacent elements in a range
(function template) [edit] sums up or folds a range of elements
(function template) [edit] similar to std::partial_sum, includes the ith input element in the ith sum
(function template) [edit] similar to std::partial_sum, excludes the ith input element from the ith sum
(function template) [edit]

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