Call signature
(1) (since C++20) (2) (since C++20)Helper types
template< class I, class O >
using rotate_copy_result = in_out_result<I, O>;
Copies the left rotation of [
first,
last)
to result.
1) Copies the elements from the source range [
first,
last)
, such that in the destination range, the elements in [
first,
middle)
are placed after the elements in [
middle,
last)
while the orders of the elements in both ranges are preserved.
The behavior is undefined if either [
first,
middle)
or [
middle,
last)
is not a valid range, or the source and destination ranges overlap.
The function-like entities described on this page are algorithm function objects (informally known as niebloids), that is:
{last, result + N}, where N = ranges::distance(first, last).
[edit] ComplexityLinear: exactly N assignments.
[edit] NotesIf the value type is TriviallyCopyable and the iterator types satisfy contiguous_iterator
, implementations of ranges::rotate_copy
usually avoid multiple assignments by using a "bulk copy" function such as std::memmove.
See also the implementations in libstdc++ and MSVC STL.
struct rotate_copy_fn { template<std::forward_iterator I, std::sentinel_for<I> S, std::weakly_incrementable O> requires std::indirectly_copyable<I, O> constexpr ranges::rotate_copy_result<I, O> operator()(I first, I middle, S last, O result) const { auto c1 {ranges::copy(middle, std::move(last), std::move(result))}; auto c2 {ranges::copy(std::move(first), std::move(middle), std::move(c1.out))}; return {std::move(c1.in), std::move(c2.out)}; } template<ranges::forward_range R, std::weakly_incrementable O> requires std::indirectly_copyable<ranges::iterator_t<R>, O> constexpr ranges::rotate_copy_result<ranges::borrowed_iterator_t<R>, O> operator()(R&& r, ranges::iterator_t<R> middle, O result) const { return (*this)(ranges::begin(r), std::move(middle), ranges::end(r), std::move(result)); } }; inline constexpr rotate_copy_fn rotate_copy {};[edit] Example
#include <algorithm> #include <iostream> #include <iterator> #include <vector> int main() { std::vector<int> src {1, 2, 3, 4, 5}; std::vector<int> dest(src.size()); auto pivot = std::ranges::find(src, 3); std::ranges::rotate_copy(src, pivot, dest.begin()); for (int i : dest) std::cout << i << ' '; std::cout << '\n'; // copy the rotation result directly to the std::cout pivot = std::ranges::find(dest, 1); std::ranges::rotate_copy(dest, pivot, std::ostream_iterator<int>(std::cout, " ")); std::cout << '\n'; }
Output:
[edit] See alsoRetroSearch is an open source project built by @garambo | Open a GitHub Issue
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