[[noreturn]] void _Exit( int exit_code ) noexcept;
(since C++11)Causes normal program termination to occur without completely cleaning the resources.
Destructors of variables with automatic, thread local and static storage durations are not called. Functions passed to std::at_quick_exit() or std::atexit() are not called. Whether open resources such as files are closed is implementation defined.
If exit_code
is 0 or EXIT_SUCCESS, an implementation-defined status indicating successful termination is returned to the host environment. If exit_code
is EXIT_FAILURE, an implementation-defined status, indicating unsuccessful termination, is returned. In other cases implementation-defined status value is returned.
A freestanding implementation is required to provide std::_Exit
.
(none)
[edit] NotesAlthough _Exit
is required to be freestanding since C++23, it is not required to be available in a freestanding C implementation.
#include <iostream> class Static { public: ~Static() { std::cout << "Static dtor\n"; } }; class Local { public: ~Local() { std::cout << "Local dtor\n"; } }; Static static_variable; // dtor of this object will *not* be called void atexit_handler() { std::cout << "atexit handler\n"; } int main() { Local local_variable; // dtor of this object will *not* be called // handler will *not* be called const int result = std::atexit(atexit_handler); if (result != 0) { std::cerr << "atexit registration failed\n"; return EXIT_FAILURE; } std::cout << "test" << std::endl; // flush from std::endl // needs to be here, otherwise nothing will be printed std::_Exit(EXIT_FAILURE); }
Output:
[edit] See also causes abnormal program termination (without cleaning up)RetroSearch is an open source project built by @garambo | Open a GitHub Issue
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