template< class T >
struct is_bind_expression;
If T is a type produced by a call to std::bind (but not std::bind_front or std::bind_back), this template is derived from std::true_type. For any other type (unless user-specialized), this template is derived from std::false_type.
A program may specialize this template for a program-defined type T to implement UnaryTypeTrait with base characteristic of std::true_type to indicate that T should be treated by std::bind as if it were the type of a bind subexpression: when a bind-generated function object is invoked, a bound argument of this type will be invoked as a function object and will be given all the unbound arguments passed to the bind-generated object.
template< class T >
constexpr bool is_bind_expression_v = is_bind_expression<T>::value;
T is a function object generated by std::bind, false otherwise
#include <functional>
#include <iostream>
#include <type_traits>
struct MyBind
{
typedef int result_type;
int operator()(int a, int b) const { return a + b; }
};
namespace std
{
template<>
struct is_bind_expression<MyBind> : public true_type {};
}
int f(int n1, int n2)
{
return n1 + n2;
}
int main()
{
// as if bind(f, bind(MyBind(), _1, _2), 2)
auto b = std::bind(f, MyBind(), 2);
std::cout << "Adding 2 to the sum of 10 and 11 gives " << b(10, 11) << '\n';
}
Output:
Adding 2 to the sum of 10 and 11 gives 23[edit] Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
[edit] See also binds one or more arguments to a function objectRetroSearch is an open source project built by @garambo | Open a GitHub Issue
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