template< class T >
struct remove_pointer;
Provides the member typedef type which is the type pointed to by T, or, if T is not a pointer, then type is the same as T.
If the program adds specializations for std::remove_pointer, the behavior is undefined.
type the type pointed to by T or T if it's not a pointer [edit] Helper types
template< class T >
using remove_pointer_t = typename remove_pointer<T>::type;
template<class T> struct remove_pointer { typedef T type; };
template<class T> struct remove_pointer<T*> { typedef T type; };
template<class T> struct remove_pointer<T* const> { typedef T type; };
template<class T> struct remove_pointer<T* volatile> { typedef T type; };
template<class T> struct remove_pointer<T* const volatile> { typedef T type; };[edit] Example [edit] See also
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