template< class RandomIt >
void nth_element( RandomIt first, RandomIt nth, RandomIt last );
void nth_element( ExecutionPolicy&& policy,
void nth_element( RandomIt first, RandomIt nth, RandomIt last,
void nth_element( ExecutionPolicy&& policy,
RandomIt first, RandomIt nth, RandomIt last,
nth_element
rearranges elements in [
first,
last)
such that after the rearrangement:
[
first,
last)
were sorted.[
first,
nth)
and every iterator j in [
nth,
last)
, the following condition is met:is
false.
3,4) bool(comp(*j, *i)) is false.
1)Elements are hypothetically
sortedwith respect to
operator<(until C++20)std::less{}(since C++20).
3) Elements are hypothetically sorted with respect to comp.
2,4) Same as (1,3), but executed according to policy.
These overloads participate in overload resolution only if all following conditions are satisfied:
If any of the following conditions is satisfied, the behavior is undefined:
[
first,
nth)
or [
nth,
last)
is not a valid range.The signature of the comparison function should be equivalent to the following:
bool cmp(const Type1& a, const Type2& b);
While the signature does not need to have const&, the function must not modify the objects passed to it and must be able to accept all values of type (possibly const) Type1
and Type2
regardless of value category (thus, Type1&
is not allowed, nor is Type1
unless for Type1
a move is equivalent to a copy(since C++11)).
The types Type1 and Type2 must be such that an object of type RandomIt can be dereferenced and then implicitly converted to both of them. â
RandomIt
must meet the requirements of LegacyRandomAccessIterator. -Compare
must meet the requirements of Compare. [edit] Complexity
Given \(\scriptsize N\)N as last - first:
1) \(\scriptsize O(N)\)O(N)comparisons using
operator<(until C++20)std::less{}(since C++20)on average.
2) \(\scriptsize O(N)\)O(N)comparisons using
operator<(until C++20)std::less{}(since C++20), and
\(\scriptsize O(N \cdot \log(N))\)O(N·log(N))swaps.
3) \(\scriptsize O(N)\)O(N) applications of the comparator comp on average.
4) \(\scriptsize O(N)\)O(N) applications of the comparator comp, and \(\scriptsize O(N \cdot \log(N))\)O(N·log(N)) swaps.
[edit] ExceptionsThe overloads with a template parameter named ExecutionPolicy
report errors as follows:
ExecutionPolicy
is one of the standard policies, std::terminate is called. For any other ExecutionPolicy
, the behavior is implementation-defined.See also the implementations in libstdc++, libc++, and MSVC STL.
[edit] NotesThe algorithm used is typically Introselect although other Selection algorithm with suitable average-case complexity are allowed.
[edit] Example#include <algorithm> #include <cassert> #include <functional> #include <iostream> #include <numeric> #include <vector> void printVec(const std::vector<int>& vec) { std::cout << "v = {"; for (char sep[]{0, ' ', 0}; const int i : vec) std::cout << sep << i, sep[0] = ','; std::cout << "};\n"; } int main() { std::vector<int> v{5, 10, 6, 4, 3, 2, 6, 7, 9, 3}; printVec(v); auto m = v.begin() + v.size() / 2; std::nth_element(v.begin(), m, v.end()); std::cout << "\nThe median is " << v[v.size() / 2] << '\n'; // The consequence of the inequality of elements before/after the Nth one: assert(std::accumulate(v.begin(), m, 0) < std::accumulate(m, v.end(), 0)); printVec(v); // Note: comp function changed std::nth_element(v.begin(), v.begin() + 1, v.end(), std::greater{}); std::cout << "\nThe second largest element is " << v[1] << '\n'; std::cout << "The largest element is " << v[0] << '\n'; printVec(v); }
Possible output:
v = {5, 10, 6, 4, 3, 2, 6, 7, 9, 3}; The median is 6 v = {3, 2, 3, 4, 5, 6, 10, 7, 9, 6}; The second largest element is 9 The largest element is 10 v = {10, 9, 6, 7, 6, 3, 5, 4, 3, 2};[edit] Defect reports
The following behavior-changing defect reports were applied retroactively to previously published C++ standards.
DR Applied to Behavior as published Correct behavior LWG 2150 C++98 after the rearrangement, only one element before nth[
first,
nth)
and [
nth,
last)
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