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Showing content from https://developer.mozilla.org/zh-TW/docs/Web/JavaScript/Reference/Global_Objects/Set/delete below:

Set.prototype.delete() - JavaScript | MDN

Set.prototype.delete()

Baseline Widely available

delete() 方法會一個 Set 物件中移除指定元素。

嘗試一下
const set1 = new Set();
set1.add({ x: 10, y: 20 }).add({ x: 20, y: 30 });

// Delete any point with `x > 10`.
set1.forEach((point) => {
  if (point.x > 10) {
    set1.delete(point);
  }
});

console.log(set1.size);
// Expected output: 1
語法 參數'
value

要從 Set 物件中移除的值。

回傳值

true 如果成功從 Set 物件中移除;反之 false。

範例 使用 delete 方法
var mySet = new Set();
mySet.add("foo");

mySet.delete("bar"); // Returns false. No "bar" element found to be deleted.
mySet.delete("foo"); // Returns true.  Successfully removed.

mySet.has("foo"); // Returns false. The "foo" element is no longer present.

下方展示了如何從一個 Set 中移除物件。

var setObj = new Set(); // Create a New Set.

setObj.add({ x: 10, y: 20 }); // Add object in the set.

setObj.add({ x: 20, y: 30 }); // Add object in the set.

// Delete any point with `x > 10`.
setObj.forEach(function (point) {
  if (point.x > 10) {
    setObj.delete(point);
  }
});
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