Baseline Widely available
The sort() method of TypedArray instances sorts the elements of a typed array in place and returns the reference to the same typed array, now sorted. This method has the same algorithm as Array.prototype.sort(), except that it sorts the values numerically instead of as strings by default.
const uint8 = new Uint8Array([40, 10, 50, 20, 30]);
uint8.sort();
console.log(uint8);
// Expected output: Uint8Array [10, 20, 30, 40, 50]
compareFn Optional
A function that determines the order of the elements. The function is called with the following arguments:
a
The first element for comparison.
b
The second element for comparison.
It should return a number where:
a should come before b.a should come after b.NaN indicates that a and b are considered equal.To memorize this, remember that (a, b) => a - b sorts numbers in ascending order.
If omitted, the typed array elements are sorted according to numeric value.
The reference to the original typed array, now sorted. Note that the typed array is sorted in place, and no copy is made.
DescriptionSee Array.prototype.sort() for more details. This method is not generic and can only be called on typed array instances.
For more examples, see also the Array.prototype.sort() method.
let numbers = new Uint8Array([40, 1, 5, 200]);
numbers.sort();
// Uint8Array [ 1, 5, 40, 200 ]
// Unlike plain Arrays, a compare function is not required
// to sort the numbers numerically.
// Regular Arrays require a compare function to sort numerically:
numbers = [40, 1, 5, 200];
numbers.sort();
// [1, 200, 40, 5]
numbers.sort((a, b) => a - b); // compare numbers
// [ 1, 5, 40, 200 ]
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