Baseline Widely available
The some() method of TypedArray instances tests whether at least one element in the typed array passes the test implemented by the provided function. It returns true if, in the typed array, it finds an element for which the provided function returns true; otherwise it returns false. It doesn't modify the typed array. This method has the same algorithm as Array.prototype.some().
function isNegative(element, index, array) {
return element < 0;
}
const int8 = new Int8Array([-10, 20, -30, 40, -50]);
const positives = new Int8Array([10, 20, 30, 40, 50]);
console.log(int8.some(isNegative));
// Expected output: true
console.log(positives.some(isNegative));
// Expected output: false
some(callbackFn)
some(callbackFn, thisArg)
callbackFn
A function to execute for each element in the typed array. It should return a truthy value to indicate the element passes the test, and a falsy value otherwise. The function is called with the following arguments:
element
The current element being processed in the typed array.
index
The index of the current element being processed in the typed array.
array
The typed array some() was called upon.
thisArg Optional
A value to use as this when executing callbackFn. See iterative methods.
false unless callbackFn returns a truthy value for a typed array element, in which case true is immediately returned.
See Array.prototype.some() for more details. This method is not generic and can only be called on typed array instances.
The following example tests whether any element in the typed array is bigger than 10.
function isBiggerThan10(element, index, array) {
return element > 10;
}
new Uint8Array([2, 5, 8, 1, 4]).some(isBiggerThan10); // false
new Uint8Array([12, 5, 8, 1, 4]).some(isBiggerThan10); // true
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