The JavaScript exception "precision is out of range" occurs when a number that's outside of the allowed range was passed into toExponential
, toFixed
, or toPrecision
.
RangeError: toExponential() argument must be between 0 and 100 (V8-based & Safari) RangeError: toFixed() digits argument must be between 0 and 100 (V8-based & Safari) RangeError: toPrecision() argument must be between 1 and 100 (V8-based & Safari) RangeError: precision -1 out of range (Firefox)Error type What went wrong?
There was an out of range precision argument in one of these methods:
Number.prototype.toExponential()
, which requires the arguments to be between 0 and 100, inclusive.Number.prototype.toFixed()
, which requires the arguments to be between 0 and 100, inclusive.Number.prototype.toPrecision()
, which requires the arguments to be between 1 and 100, inclusive.(77.1234).toExponential(-1); // RangeError
(77.1234).toExponential(101); // RangeError
(2.34).toFixed(-100); // RangeError
(2.34).toFixed(1001); // RangeError
(1234.5).toPrecision(-1); // RangeError
(1234.5).toPrecision(101); // RangeError
Valid cases
(77.1234).toExponential(4); // 7.7123e+1
(77.1234).toExponential(2); // 7.71e+1
(2.34).toFixed(1); // 2.3
(2.35).toFixed(1); // 2.4 (note that it rounds up in this case)
(5.123456).toPrecision(5); // 5.1235
(5.123456).toPrecision(2); // 5.1
(5.123456).toPrecision(1); // 5
See also
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