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Date.prototype.getYear() - JavaScript | MDN

已弃用: 不再推荐使用该特性。虽然一些浏览器仍然支持它，但也许已从相关的 web 标准中移除，也许正准备移除或出于兼容性而保留。请尽量不要使用该特性，并更新现有的代码；参见本页面底部的兼容性表格以指导你作出决定。请注意，该特性随时可能无法正常工作。

getYear() 方法返回指定的本地日期的年份。因为 getYear() 不返回千禧年（"year 2000 problem"），所以这个方法不再被使用，现在替换为 getFullYear。

getYear 方法返回一个年份减去 1900 的值；因此：

• 如果年份大于等于 2000，则 getYear() 的返回值将大于等于 100。例如，如果年份是 2026，则 getYear() 返回 126。
• 如果年份在 1900 到 1999 之间，getYear() 的返回值将在 0 到 99 之间。例如，如果年份是 1976，则 getYear() 返回 76。
• 如果年份小于 1900，则 getYear() 的返回值将小于 0。例如，如果年份是 1800，则 getYear() 返回 -100。

如果要同时考虑 2000 年之前和之后的年份，应该使用 getFullYear() 而不是 getYear()，以便指定完整年份。

The getYear method returns either a 2-digit or 4-digit year:

• For years between and including 1900 and 1999, the value returned by getYear is the year minus 1900. For example, if the year is 1976, the value returned is 76.
• For years less than 1900 or greater than 1999, the value returned by getYear is the four-digit year. For example, if the year is 1856, the value returned is 1856. If the year is 2026, the value returned is 2026.

The second statement assigns the value 95 to the variable year.

var Xmas = new Date("December 25, 1995 23:15:00");
var year = Xmas.getYear(); // returns 95

The second statement assigns the value 100 to the variable year.

var Xmas = new Date("December 25, 2000 23:15:00");
var year = Xmas.getYear(); // returns 100

The second statement assigns the value -100 to the variable year.

var Xmas = new Date("December 25, 1800 23:15:00");
var year = Xmas.getYear(); // returns -100

The second statement assigns the value 95 to the variable year, representing the year 1995.

var Xmas.setYear(95);
var year = Xmas.getYear(); // returns 95

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